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There are 2 components in parallel. When the system is operational you are in State 1. If the first 1 component fails the system moves to state 2 but the second component operates and carries the load If the second component fails but the first component is still operating the state is in State 3. Finally if in state 2 or state 3 and the remaining component fails the state is changed to State 4. The state equations for the system just described are shown below: dP₁ (t)/dt = -(1₁+12)P₁ (t), dP2(t)/dt = 1₁P₁ (t) -13P2(t), dP3(t)/dt = 12P₁ (t) -14P3(t), P₁+P 2+P3+P4=1. . These equations are correct and sufficient to solve for state probabilities.

There are 2 components in parallel. When the system is operational you are in State 1. If the first 1 component fails the system moves to state 2 but the second component operates and carries the load If the second component fails but the first component is still operating the state is in State 3. Finally if in state 2 or state 3 and the remaining component fails the state is changed to State 4. The state equations for the system just described are shown below: dP₁ (t)/dt = -(1₁+12)P₁ (t), dP2(t)/dt = 1₁P₁ (t) -13P2(t), dP3(t)/dt = 12P₁ (t) -14P3(t), P₁+P 2+P3+P4=1. . These equations are correct and sufficient to solve for state probabilities.

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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The minimal cut sets for a series system is always a lower bound on Reliability. True False The minimal path sets for a series system is always an upper bound on reliability. True False
Transcribed Image Text:The minimal cut sets for a series system is always a lower bound on Reliability. True False The minimal path sets for a series system is always an upper bound on reliability. True False
There are 2 components in parallel. When the system is operational you are in State 1. If the first 1 component fails the system moves to state 2 but the second component operates and carries the load If the second component fails but the first component is still operating the state is in State 3. Finally if in state 2 or state 3 and the remaining component fails the state is changed to State 4. The state equations for the system just described are shown below: dP, (t)/dt = -(1,+l2)P,(t), dP2(t)/dt = 1,P, (t) -13P2(t), dP3(t)/dt =l½P¡(t) -1¼P3(t), P1+P2+P3+P4=1. . These equations are correct and sufficient to solve for state probabilities. 1 2 21 12 2.3 3 14 True False
Transcribed Image Text:There are 2 components in parallel. When the system is operational you are in State 1. If the first 1 component fails the system moves to state 2 but the second component operates and carries the load If the second component fails but the first component is still operating the state is in State 3. Finally if in state 2 or state 3 and the remaining component fails the state is changed to State 4. The state equations for the system just described are shown below: dP, (t)/dt = -(1,+l2)P,(t), dP2(t)/dt = 1,P, (t) -13P2(t), dP3(t)/dt =l½P¡(t) -1¼P3(t), P1+P2+P3+P4=1. . These equations are correct and sufficient to solve for state probabilities. 1 2 21 12 2.3 3 14 True False
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