Thinking x 2 s+2t 23. Find a normal vector of the plane: y = 3 + 4s - 3t z=4+s+ 4t 24. The point (-2, k, 7) lies on the plane: 4x+5y + 12z 16 = 0. Find the value of k. - 25. Determine if the point (-1, 11) is on the line defined by (x - 3, y − 1) = t (-2, 5), te R.) 26. Find the intercepts of the plane [x, y, z] = [5, 4, 3] + s [1, 0, 1] + t [−1, −4, −2].
Thinking x 2 s+2t 23. Find a normal vector of the plane: y = 3 + 4s - 3t z=4+s+ 4t 24. The point (-2, k, 7) lies on the plane: 4x+5y + 12z 16 = 0. Find the value of k. - 25. Determine if the point (-1, 11) is on the line defined by (x - 3, y − 1) = t (-2, 5), te R.) 26. Find the intercepts of the plane [x, y, z] = [5, 4, 3] + s [1, 0, 1] + t [−1, −4, −2].
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter5: Inner Product Spaces
Section5.1: Length And Dot Product In R^n
Problem 17E: Consider the vector v=(1,3,0,4). Find u such that a u has the same direction as v and one-half of...
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![Thinking
x 2 s+2t
23. Find a normal vector of the plane: y = 3 + 4s - 3t
z=4+s+ 4t
24. The point (-2, k, 7) lies on the plane: 4x+5y + 12z 16 = 0. Find the value of k.
-
25. Determine if the point (-1, 11) is on the line defined by (x - 3, y − 1) = t (-2, 5), te R.)
26. Find the intercepts of the plane [x, y, z] = [5, 4, 3] + s [1, 0, 1] + t [−1, −4, −2].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdf41df8f-e300-4854-aaa2-c9c3c769a22c%2F5fe40ac3-3fab-4c38-93d3-885216a1bf18%2F25w5s9e_processed.png&w=3840&q=75)
Transcribed Image Text:Thinking
x 2 s+2t
23. Find a normal vector of the plane: y = 3 + 4s - 3t
z=4+s+ 4t
24. The point (-2, k, 7) lies on the plane: 4x+5y + 12z 16 = 0. Find the value of k.
-
25. Determine if the point (-1, 11) is on the line defined by (x - 3, y − 1) = t (-2, 5), te R.)
26. Find the intercepts of the plane [x, y, z] = [5, 4, 3] + s [1, 0, 1] + t [−1, −4, −2].
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