This code deletes all nodes whose info field contains the value x. Please modify the code to delete the only first value of x : ( maybe we need to add one line ) ( do not care about yellow )
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Q: This code deletes all nodes whose info field contains the value x. Please modify the code to delete…
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This code deletes all nodes whose info field contains the value x.
Please modify the code to delete the only first value of x : ( maybe we need to add one line ) ( do not care about yellow )
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- //main.cpp #include "linkedListType.h"int main(){Node* head = NULL;orderedLinkedList oll = orderedLinkedList(head); oll.insert(40);oll.insert(100);oll.insert(50); oll.printList(); oll.insert(50);oll.printList(); return 0;} //linkedListType.h #include <stdio.h>#include <iostream>using namespace std; class Node{public:int data;Node* next;}; class orderedLinkedList {Node* head; public:orderedLinkedList(Node* h) {head = h;} void insert(int new_data){Node* head_ref = head; while (head_ref != NULL && (head_ref->next != NULL) && (head_ref->next)->data < new_data){cout << head_ref->data << "\n";head_ref = head_ref->next;} if (head_ref != NULL && (head_ref->next != NULL) && (head_ref->next)->data == new_data){cout << "ERROR: Item to be inserted is already in the list\n";return;} /* Insert new node */Node* new_node = new Node();new_node->data = new_data;if (head_ref != NULL) {new_node->next =…PYTHON class BSTnode: def __init__(self, key = None, left = None, right = None, parent = None): # Initialize the a node. self.__key = key # value for the node self.__left = left self.__right = right self.__parent = parent def setkey(self, newkey): # Sets the key value of the node to newkey ####################################################################### # Remove the pass and write your code ####################################################################### pass ####################################################################### # End code ####################################################################### def getkey(self): # returns the key value of the node ####################################################################### # Remove the pass and write your code #######################################################################…Given a linked list of N nodes such that it may contain a loop. A loop here means that the last node of the link list is connected to the node at position X(1-based index). If the link list does not have any loop, X=0. Remove the loop from the linked list, if it is present, i.e. unlink the last node which is forming the loop. Example 1: Input: N = 3 value[] = {1,3,4} X = 2 Output: 1 Explanation: The link li. st looks like 1 -> 3 -> 4 ^ | |____|
- BinaryNode class with Netflix data:1 // Node class to store an instance of Netflix content23 class BinaryNode4 {5 // Data6 String type; // movie or tv show7 String title; // title of movie/tv show8 int releaseYear; // release year of movie/tv show9 BinaryNode left; // left child10 BinaryNode right; // right child11 }@Override// interface method ==================================================public int merge(BST nbt) {/*See BST.java for method specification */// Hint: traverse bst using pre-order// as each node is visited, take the value there// and do this.insert(value)// have to somehow count when an add is successful// so we can return the number of nodes added/* Your code here */return 0; // Dummy return statement. Remove when you implement!} in java fill out method should merge two bst and not add duplicates09.Given a linked list of N nodes such that it may contain a loop. A loop here means that the last node of the link list is connected to the node at position X(1-based index). If the link list does not have any loop, X=0. Remove the loop from the linked list, if it is present, i.e. unlink the last node which is forming the loop. Example 1: Input: N = 3 value[] = {1,3,4} X = 2 Output: 1 Explanation: The link list looks like 1 -> 3 -> 4 ^ | |____|
- C++ Add a new leaf node called nodeM which will possess the data value of M. Make this node the child of nodeB. Perform the findData function you created in #3, what can you observe about the output? /#3 #include<iostream>#include<queue>using namespace std; struct treeNode{ char dataItem; struct treeNode *firstChild; struct treeNode *nextSibling;}; /* Preorder Traversalpreorder (v)visit(v)for each child w of vpreorder(w)*/void preorder(treeNode *currNode, char KEY){ if(currNode != NULL) { if(currNode->dataItem == KEY) { cout<<"KEY: "<<KEY<< " was found!\n"; } preorder(currNode->firstChild, KEY); preorder(currNode->nextSibling, KEY); } return;} /*Inorder Traversalif(v==NULL) returninOrder(v.left)visit(v)inOrder(v.right)*/void inorder(treeNode *currNode, char KEY){ if(currNode != NULL) { if(currNode->dataItem == KEY) { cout<<"KEY:…Write a Python code using the given function and conditions. Do not use Numpy. Use LinkedList Manipulation. Given function: def insert(self, newElement, index) Pre-condition: The list is not empty. Post-condition: This method inserts newElement at the given index of the list. If an element with the same key as newElement value already exists in the list, then it concludes the key already exists and does not insert the key. [You must also check the validity of the index].Assume a Node class has been defined using the Node class implementation in your textbook, except that the data members have been declared public instead of private. This means that the code shown below has direct access to the data members defined inside the Node class. Type the exact output produced by the following code fragment. Assume that the code compiles and executes without errors. void linkedList (void) { Node<char> *ptr1; Node<char> *ptr2; Node<char> *top; char ch; ptr1 = new Node<char>; top = ptr1; ptr1->item = 'D'; ptr1 = new Node<char>; top->next = ptr1; ptr1->item = 'E'; for (ch = 'H'; ch < 'P'; ch = ch + 3) { ptr2 = new Node<char>; ptr1->next = ptr2; ptr2->item = ch; ptr1 = ptr1->next; ptr2 = new Node<char>; ptr1->next = ptr2; ptr2->item = ch + 1; ptr1 =…
- int F(node<int>&p){int c=0; while(p!=0){p=p->next; c++; } return c;} This function is a. return the number of items in the linked list b. return the number of items in a linked list and destroy the linked list c. None of these d. destroy the list and free all allocated nodes1. The below method is used to select a nodein map coloring problem.def get_node():mnode = "length = -1for k in cgraph.keys():if(len( cgraph[k]) > length and k not inok Color.keys());length = len(cgraph[k])mnode = kreturn mnode The method will return an empty string when A. All nodes are already assigned colorsB. There is no color remaining for a nodeC. Any two nodes have only one color left Note: Select 1 answer from 3 options.(java)create a generic node class. create another class called op, that contains methods to add or delete nodes in any location.