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True or False:
The initial loop is more efficient than its vecotized equivalent?
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- Complete the following function that counts the even numbers in a 2D vector of integers. int count_evens(const std::vector<std::vector<int>>& v) { // Add your code... } Please add output screenshot!Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a space. Ex: If origList = {40, 50, 60, 70} and offsetAmount = {5, 7, 3, 0}, print: 45 57 63 70 #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> origList(NUM_VALS);vector<int> offsetAmount(NUM_VALS);unsigned int i; for (i = 0; i < origList.size(); ++i) {cin >> origList.at(i);} for (i = 0; i < offsetAmount.size(); ++i) {cin >> offsetAmount.at(i);} cout << endl; return 0;} Please help me with this problem using c++.(Write a code in C++ Programming language)Use a vector to read 10 integer numbers, each of which is between 1 and 50. Begin with an empty vector and use its push_back function to add each unique value to the vector. As each number is read, validate it and store it in the array only if it is not a duplicate of a number already read. After reading all the values, display only the unique values that the user entered.
- Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >> courseGrades.at(i); }…Resize vector countDown to have newSize elements. Populate the vector with integers {newSize, newSize - 1, …, 1}. Ex: If newSize = 3, then countDown = {3, 2, 1}, and the sample program outputs:3 2 1 Go! #include <iostream>#include <vector>using namespace std; int main() { vector<int> countDown(0); int newSize; unsigned int i; cin >> newSize; /* Your solution goes here */ for (i = 0; i < countDown.size(); ++i) { cout << countDown.at(i) << " "; } cout << "Go!" << endl; return 0;}In PYTHON Write a function that prints all elements of a vector from the first element up to the first occurrence of the element having value equal to a provide number Use while loop(s) Function Name:print_up_to_value Parameters:a_vector,a_value Return:none Example: Input: my_vector = [5,6,7,8,9,5,6,7,8,9] Invokefunction:print_up_to_value(my_vector,7) Output:[5,6,7]
- In PYTHON Write a function that prints multiple times a vector from its first element up to the next occurrence of an element having value equal to a provide number Each print stops at the i-th occurrence of the provided number Use while loop(s) Function Name:vec_multi_print_to_number Parameters:a_vector,a_value Return:none Example: Input:my_vector=[5,6,7,8,9,5,6,7,8,9] Invokefunction:print_up_to_value(my_vector,7) Output:[5,6,7,8,9,5,6,7]Vectors Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid vector element, such as courseGrades.at(9) for a 4-element vector, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() {const int NUM_VALS = 4;vector<int> courseGrades(NUM_VALS);int i; for (i = 0;…Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >> courseGrades.at(i);…
- Write a function that removes duplicates from a vector. For example, if remove duplicates is called with a vector containing 1 4 9 16 9 7 4 9 11 (use these numbers) then the vector is changed to 1 4 9 16 7 11Using C++ Using only these simpler vector methods Create a vector of at least 10 integers. Cout the vector with spaces in between the integers. Cout the vector backward. Using loops that traverse the elements, create a new vector with the elements arranged from high to low. Cout the new vector. Do not use iterators for this exercise, or any other advanced methods--only the ones listed below. Hint: Use multiple vectors, including the copying of vectors. vector<int> grades1 = {45, 67, 88, 45, 23}; vector<int> grades2 = grades1; May Only Use These Vector Methods: size() // Returns the number of elements empty() // Returns a boolean True if the vector is empty push_back(element) // Adds an element to the back of the vector pop_back() // Removes the element at the back of the vector front() // Returns the element at the front of the vector back()…Using C++ Using only these simpler vector methods Create a vector of at least 10 integers. Cout the vector with spaces in between the integers. Cout the vector backward. Using loops that traverse the elements, create a new vector with the elements arranged from high to low. Cout the new vector. Do not use iterators for this exercise, or any other advanced methods--only the ones listed below. Hint: Use multiple vectors, including the copying of vectors. vector<int> grades1 = {45, 67, 88, 45, 23}; vector<int> grades2 = grades1; May Only Use These Vector Methods: size() // Returns the number of elements empty() // Returns a boolean True if the vector is empty push_back(element) // Adds an element to the back of the vector pop_back() // Removes the element at the back of the vector front() // Returns the element at the front of the vector back()…