This question is designed to be answered with a calculator. The equation of the line tangent to the graph of f(x) = 5¹-x² at x = 1 is O y= -2x+1. O y=-2x + 3. O y = -2(In 5)x + 1. O y = -2(In 5)(x − 1) + 1.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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could someone solve this please?

This question is designed to be answered with a calculator.
The equation of the line tangent to the graph of f(x) = 5¹-x² at x = 1 is
O y= -2x+1.
O y=-2x + 3.
O y = -2(In 5)x + 1.
O y = -2(In 5)(x − 1) + 1.
Transcribed Image Text:This question is designed to be answered with a calculator. The equation of the line tangent to the graph of f(x) = 5¹-x² at x = 1 is O y= -2x+1. O y=-2x + 3. O y = -2(In 5)x + 1. O y = -2(In 5)(x − 1) + 1.
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