I do not understand the derribation on the right. 5+yThus, the equation of the streamline passing through point (1 m, 2 m) is x²буDetermine the derivative of the equation with respect to y.бу (3у?)-(у+5) (6)(бу?18у -бу-30- dx2x drdy36y?dx2xdy2y³–5бу?dx2y-5dy12xy2Set the derivative d = 0 and rewrite the above equation.2y³–50 =12xy22y – 5 = 0y = 1.357 mDetermine the corresponding value of x.5+yx²бу5+(1.357 m)x²=6(1.357 m)x = 0.960 m

The given equation is of streamlined flow.

Thus, the equation of the streamline passing through point (1 m, 2 m) is x² = Determine the derivative of the equation with respect to y. 6y(3y²)-(y³+5)(6) (бу? 18y -бу-30 36у? 2r4 dy 2rd dy 2y³–5 6y? dy 2y³–5 dy 12xy? Set the derivative d = 0 and rewrite the above equation. 2y³–5 0 = 12xy2 2у — 5 %3D 0 y = 1.357 m Determine the corresponding value of x. 5+y x = бу 5+(1.357 m) 6(1.357 m) x? : x = 0.960 m

Thus, the equation of the streamline passing through point (1 m, 2 m) is x² = Determine the derivative of the equation with respect to y. 6y(3y²)-(y³+5)(6) (бу? 18y -бу-30 36у? 2r4 dy 2rd dy 2y³–5 6y? dy 2y³–5 dy 12xy? Set the derivative d = 0 and rewrite the above equation. 2y³–5 0 = 12xy2 2у — 5 %3D 0 y = 1.357 m Determine the corresponding value of x. 5+y x = бу 5+(1.357 m) 6(1.357 m) x? : x = 0.960 m

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter5: Analysis Of Convection Heat Transfer

Section: Chapter Questions

Problem 5.3P: Evaluate the Nusselt number for flow over a sphere for the following conditions: D=0.15m,k=0.2W/mK,...

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