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To answer the questions below, it may be useful to think of your friend's car driving on a level road on the surface of the Earth, or maybe in space accelerating upwards at 9.8 m/s? (or some other rate of acceleration, depending on the question). 1) Rearview mirror Spring Fuzzy dice Your friend starts out by hanging is fuzzy dice from a spring. On the surface of the Earth, he finds the length of the spring to be 8.5 cm. With his car drifting in space (as in diagram B, above) he finds the length of the spring to be 3.6 cm (this is called the equilibrium length of the spring). What would be the length of the spring in a situation similar to diagram C above, if the car were accelerating upward at a rate of 9.8 m/s? 8.5 cm Submit + 2) If the spring is supporting the dice on the surface of a planet, the amount that the spring stretches (the difference between its length and its equilibrium length, 3.6 cm) is directly proportional to the strength of gravity on that planet. If it is pulling the fuzzy dice in space with zero gravity, the difference between its length the equilibrium length is directly proportional to the acceleration of the rocket ship. What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 12.6 m/s? cm Submit + 3) What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 6.8 m/s? cm Submit +

To answer the questions below, it may be useful to think of your friend's car driving on a level road on the surface of the Earth, or maybe in space accelerating upwards at 9.8 m/s? (or some other rate of acceleration, depending on the question). 1) Rearview mirror Spring Fuzzy dice Your friend starts out by hanging is fuzzy dice from a spring. On the surface of the Earth, he finds the length of the spring to be 8.5 cm. With his car drifting in space (as in diagram B, above) he finds the length of the spring to be 3.6 cm (this is called the equilibrium length of the spring). What would be the length of the spring in a situation similar to diagram C above, if the car were accelerating upward at a rate of 9.8 m/s? 8.5 cm Submit + 2) If the spring is supporting the dice on the surface of a planet, the amount that the spring stretches (the difference between its length and its equilibrium length, 3.6 cm) is directly proportional to the strength of gravity on that planet. If it is pulling the fuzzy dice in space with zero gravity, the difference between its length the equilibrium length is directly proportional to the acceleration of the rocket ship. What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 12.6 m/s? cm Submit + 3) What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 6.8 m/s? cm Submit +

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Please do questions 2, 3, 6, and 7.

To answer the questions below, it may be useful to think of your friend's car driving on a level road on the surface of the Earth, or maybe in space accelerating upwards at 9.8 m/s2 (or some other rate of acceleration, depending on the question). 1) Rearview mirror Spring Fuzzy dice Your friend starts out by hanging is fuzzy dice from a spring. On the surface of the Earth, he finds the length of the spring to be 8.5 cm. With his car drifting in space (as in diagram B, above) he finds the length of the spring to be 3.6 cm (this is called the equilibrium length of the spring). What would be the length of the spring in a situation similar to diagram C above, if the car were accelerating upward at a rate of 9.8 m/s? 8.5 cm Submit 2) If the spring is supporting the dice on the surface of a planet, the amount that the spring stretches (the difference between its length and its equilibrium length, 3.6 cm) is directly proportional to the strength of gravity on that planet. If it is pulling the fuzzy dice in space with zero gravity, the difference between its length the equilibrium length is directly proportional to the acceleration of the rocket ship. What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 12.6 m/s? cm Submit 3) What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 6.8 m/s? cm Submit +
Transcribed Image Text:To answer the questions below, it may be useful to think of your friend's car driving on a level road on the surface of the Earth, or maybe in space accelerating upwards at 9.8 m/s2 (or some other rate of acceleration, depending on the question). 1) Rearview mirror Spring Fuzzy dice Your friend starts out by hanging is fuzzy dice from a spring. On the surface of the Earth, he finds the length of the spring to be 8.5 cm. With his car drifting in space (as in diagram B, above) he finds the length of the spring to be 3.6 cm (this is called the equilibrium length of the spring). What would be the length of the spring in a situation similar to diagram C above, if the car were accelerating upward at a rate of 9.8 m/s? 8.5 cm Submit 2) If the spring is supporting the dice on the surface of a planet, the amount that the spring stretches (the difference between its length and its equilibrium length, 3.6 cm) is directly proportional to the strength of gravity on that planet. If it is pulling the fuzzy dice in space with zero gravity, the difference between its length the equilibrium length is directly proportional to the acceleration of the rocket ship. What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 12.6 m/s? cm Submit 3) What would be the length of the spring in a situation similar to diagram C above if the car were accelerating upward at a rate of 6.8 m/s? cm Submit +
6) In the diagram in question 4, the angle between the string and the vertical line is theta = 27 degrees. What is the normal component (also known as the radial component) of the acceleration of the car at this time? [HINT: It might (and then again it might not) be useful to imagine this happening in space with a car that is accelerating upward and in a radial direction.] m/s2 Submit 7) At the time shown in the diagram at the bottom of question 4, the car was going around a curve with a radius of curvature of 46 m. What was the speed of the car? m/s Submit
Transcribed Image Text:6) In the diagram in question 4, the angle between the string and the vertical line is theta = 27 degrees. What is the normal component (also known as the radial component) of the acceleration of the car at this time? [HINT: It might (and then again it might not) be useful to imagine this happening in space with a car that is accelerating upward and in a radial direction.] m/s2 Submit 7) At the time shown in the diagram at the bottom of question 4, the car was going around a curve with a radius of curvature of 46 m. What was the speed of the car? m/s Submit
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