To draw a line between (5,12) and (15,20) by using Bresenham algorithm In step (6) The Pk+1=. ............... 2 4 7 -2
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- Minimize the block diagram above. (Find C (s) / R (s)). (Solve each step in detail andindicate by drawing.)Fibonacci principle states that: If we let Xn be the nth integer of the sequence, then the next (n+1)th integer is equal to the sum of nth and (n-1)th integers. Xn+1 = Xn+Xn-1 Using the principle, derive some equations relative to the Fibonacci numbers.Lesson: Operaitons Research Solve with Prim Algorithm and Given Data AC:9 AD:9 AE:3 DC:3 CF:8 BD:6 BG:5 GC:3 DF:9 GE:7 BE:3 EF:4
- Know the difference between A* and Dijkstra's algorithm (pp. 241-243)Using the following code of the Simplified Bresenham algorithm, show the complete steps for drawing a line from the point (1, -3) to the point (-4, 0) in a 2D Cartesian domain. function line(x0, y0, x1, y1)dx := abs(x1-x0)dy := abs(y1-y0) if x0 < x1 then sx := 1 else sx := -1if y0 < y1 then sy := 1 else sy := -1err := dx-dyloopplot(x0,y0)if x0 = x1 and y0 = y1 exit loope2 := 2*errif e2 > -dy then err := err - dyx0 := x0 + sxend ifif x0 = x1 and y0 = y1 then plot(x0,y0)exit loopend ifif e2 < dx then err := err + dxy0 := y0 + sy end ifend loopevaluate nCxpxqn-x for the values of n, x, and p given in Problem A) n= 4, x= 2, p=1/2
- Two points on line 1 are given as (x1, y1) and (x2,y2) and on line 2 as (x3, y3) and (x4, y4), as shown in Figure 3.8a and b.The intersecting point of the two lines can be found by solving the following linearequations:(y1 - y2)x - (x1 - x2)y = (y1 - y2)x1 - (x1 - x2)y1(y3 - y4)x - (x3 - x4)y = (y3 - y4)x3 - (x3 - x4)y3This linear equation can be solved using Cramer’s rule . If the equation has no solutions, the two lines are parallel (see Figure). Write a program that prompts the user to enter four points and displays the intersectingpoint. Here are sample runs:Discrete mathematics Show step by step how to solve this. The answer is provided.SHOW ALL STEPS Use K-Maps to simplify each of the following: ~x~y~z + ~xy~z + x~y~z + xy~z 2. ~y~z + ~yz + xy~z
- Draw a line between P0=(2,3) and Pe=(6,9) using 1- Normal algorithm 2- Presenham's algorithmTo what end does Booth's algorithm seek to solve problems?6. Algebraically find the conjunctive normal form of the following expression. P ⇒ ((Q∧R) ⇔ S) Justify every step with the law (or laws) you use for the step