To evaluate x²cosx dx use integration by parts. What is the expression after the second integration by parts? x2sinx + 2x cost – 2 2 / COST cosx dx + C x’sinx+2x cosx – 2 2f sinx dx + C x’sinx – 2x cost – 2 2S CONT cosx dx + C x2sinx − 2x cosx+2 2fcos cosx dx + C B

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...
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To evaluate
Jacost
x²cosx dx use integration by parts. What is the expression after the second integration by parts?
x’sinx+2x cost – 2
2 fo
cosx dx + C
x’sinx + 2x cost – 2
-2 sinx d
sinx dx + C
x2sinx – 2x cosx – 2
S
cosx dx + C
x2sinx — 2x cosx+2
fo
cosx dx + C
B
Transcribed Image Text:To evaluate Jacost x²cosx dx use integration by parts. What is the expression after the second integration by parts? x’sinx+2x cost – 2 2 fo cosx dx + C x’sinx + 2x cost – 2 -2 sinx d sinx dx + C x2sinx – 2x cosx – 2 S cosx dx + C x2sinx — 2x cosx+2 fo cosx dx + C B
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