To evaluate [x²cosx dx. Use integration by parts. What is the expression after the second integration by parts? x’sinx – 2x cosx − 2 | cosx dx +C -2 / COST x²sinx + 2x cosx-2 sinx dx + C -2 sinx o x’sinx+2x cosx − 2 | cosx dx + C -2 / COST x’sinx – 2x cosx+2 | cosx dx+C +2 / COST

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...
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[x²COST
x²cosx dx use integration by parts. What is the expression after the second integration by parts?
x2sinx − 2x cost – 2
2 / COST
cosx dx + C
x2sinx+2x cost=
2 f sinx
sinx dx + C
x2sinx+2x cosx– 2
2 f co
cosx dx + C
x2sinx – 2x cosx+2
2 fcOSX
cosx dx + C
To evaluate
Transcribed Image Text:[x²COST x²cosx dx use integration by parts. What is the expression after the second integration by parts? x2sinx − 2x cost – 2 2 / COST cosx dx + C x2sinx+2x cost= 2 f sinx sinx dx + C x2sinx+2x cosx– 2 2 f co cosx dx + C x2sinx – 2x cosx+2 2 fcOSX cosx dx + C To evaluate
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