To find the arclength of y = 2x2 - 2 from a = 0 to x = 5, which is the correct integral? OL= VI+ 16rdx OL= V1+ 4xdx OL = V1+ 16 da OL= | V1+ 4x dx Now that you have the correct integral, use the substitution u = 4x to re-write the integral in terms of u. Which is the correct result? OL = 4 VI+ udu 20 OL= 4. V1+ 4udu 20 V1+ 2u'du OL = 20 V1 + u'du OL = Jo What is the value of the integral? Hint: Use formula #21 in the Table of Integrals at the back of your text. You may enter a decimal approximation for your solution.

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