To find the arclength of y = 4x² - 3 from a = 0 to x = 4, which is the correct integral? √ VI + Sada √I+64zdz OL= OL= L = √² OL= OL= Now that you have the correct integral, use the substitution u = 8x to re-write the integral in terms of u. Which is the correct result? √1+8x²dx f /* √1 +64x² dx OL== COL= OL= 11. 0 32 1 OL= = √1 +4u² du 1 32 0 10 32 √1+8udu 32 √1+ udu √1+ u²du What is the value of the integral? Hint: Use formula #21 in the Table of Integrals at the back of your text. You may enter a decimal approximation for your solution.

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