To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one turn of the helix with the following parameterizations. a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, 0sts b. r(t) = | cos i+ sin -k. 0sts 4 2. c. r(t) = (cos t)i – (sin t)j – tk, - 21sts0 Note that the helix shown to the right is just one example of such a helix, and does not exactly correspond to the DATAMstrisotiono in Bata a a. L= (Type an exact answer, using t as needed.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 77E
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20
13.3.18
To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it,
calculate the length of one turn of the helix with the following parameterizations.
a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, 0sts
2
b. r(t) = cos
i+ sin
2.
k, 0sts4m
+.
2.
C. r(t) = (cos t)i – (sin t)j – tk,
- 2nsts0
Note that the helix shown to the right is just one example of such a helix, and does not exactly correspond to the
ationo in noto o
a. L= |Type an exact answer, using A as needed)
Enter your answer in the answer box and then click Check Answer.
2 parts
remaining
Clear ll
Transcribed Image Text:20 13.3.18 To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one turn of the helix with the following parameterizations. a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, 0sts 2 b. r(t) = cos i+ sin 2. k, 0sts4m +. 2. C. r(t) = (cos t)i – (sin t)j – tk, - 2nsts0 Note that the helix shown to the right is just one example of such a helix, and does not exactly correspond to the ationo in noto o a. L= |Type an exact answer, using A as needed) Enter your answer in the answer box and then click Check Answer. 2 parts remaining Clear ll
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