to prove the Statement. (Assume that Statement: For all sets A, B, and C, (A - B) n (C - B) = (A N C) – B. Proof: Suppose A, B, and C are any sets. [To show that (A - B) N (C – B) = (A N C) - B, we must show that (A – B) n (C – B) C (A N C) – Band that (A n C) - BE (A - B) n (C - B).] Part 1: Proof that (A - B) N (C – B) C (A N C) - B Consider the sentences in the following scrambled list. Thus x E ANC by definition of intersection, and, in addition, x € B. Therefore x E (AN C) - B by the definition of set difference. By definition of set difference, x E A - Band x EC - B. By definition of intersection, x E A and x EB and x E C and x € B. By definition of intersection, x E A - B and x EC - B. By definition of set difference, x E A and x € B and x E C and x € B. To prove Part 1, select sentences from the list and put them in the correct order. 1. Suppose x € (A – B) N (C – B). 2. --Select--. 3. ---Select-. 4. ---Select--- 5. ---Select-. 6. Hence, (A - B) n (C - B) S (AN C) - B by definition of subset. Part 2: Proof that (A N C) – BC (A – B) N (C – B) Consider the sentences in the following scrambled list. By definition of intersection, x € (A - B) n (C - B). By definition of intersection x E AnC and x € B. By definition of set difference, x E A and x E C. By definition of set difference x E ANC and x ¢ B. Hence both x E A and x € B and also x E C, and x € B. So by definition of set difference, x E A - Band x E C - B. Thus, by definition of intersection, x E A and x € C, and, in addition, x ¢ B. To prove Part 2, select sentences from the list and put them in the correct order. 1. Suppose x E (AN C) - B. 2. ---Select--. 3. ---Select--- 4. ---Select.-. -Select--- 6. --Select--- 7. Hence, (A N C) - BE (A - B) n (C - B) by definition of subset. 5.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter1: Fundamentals
Section1.1: Sets
Problem 1TFE: True or False Label each of the following statements as either true or false. Two sets are equal if...
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Use an element argument to prove the statement. (Assume that all sets are subsets of a universal set U.)
Statement: For all sets A, B, and C,
(A – B) N (C – B) = (A N C) – B.
Proof:
Suppose A, B, and C are any sets. [To show that (A – B) N (C – B) = (A n C) - B, we must show that (A – B) N (C – B) C (A N C) – B and that (A n C) – BC (A – B) N (C – B).]
Part 1: Proof that (A - B) N (C – B) C (A n C) – B
Consider the sentences in the following scrambled list.
Thus x E AN C by definition of intersection, and, in addition, x € B.
Therefore x € (A N C) – B by the definition of set difference.
By definition of set difference, x E A - B and x E C - B.
By definition of intersection, x E A and x €B and x E C and x € B.
By definition of intersection, x E A - B and x E C - B.
By definition of set difference, x E A and x É B and x E C and x € B.
To prove Part 1, select sentences from the list and put them in the correct order.
1. Suppose x E (A – B) N (C - B).
2.
--Select---
3.
--Select--
4.
--Select---
5.
--Select--
6. Hence, (A – B) N (C – B) S (A N C) – B by definition of subset.
Part 2: Proof that (A N C) – BC (A – B) N (C – B)
Consider the sentences in the following scrambled list.
By definition of intersection, x € (A – B) (C – B).
By definition of intersection x € A NC and x ¢ B.
By definition of set difference, x E A and x E C.
By definition of set difference x E ANC and x € B.
Hence both xE A and x € B and also x E C, and x ¢ B.
So by definition of set difference, x E A – B and x E C - B.
Thus, by definition of intersection, x E A and x € C, and, in addition, x € B.
To prove Part 2, select sentences from the list and put them in the correct order.
1. Suppose x E (A N C) – B.
2.
--Select---
3.
-Select---
4.
--Select---
5. ---Select-
6. ---Select---
7. Hence, (A n c) - BC (A – B) N (C – B) by definition of subset.
Transcribed Image Text:Use an element argument to prove the statement. (Assume that all sets are subsets of a universal set U.) Statement: For all sets A, B, and C, (A – B) N (C – B) = (A N C) – B. Proof: Suppose A, B, and C are any sets. [To show that (A – B) N (C – B) = (A n C) - B, we must show that (A – B) N (C – B) C (A N C) – B and that (A n C) – BC (A – B) N (C – B).] Part 1: Proof that (A - B) N (C – B) C (A n C) – B Consider the sentences in the following scrambled list. Thus x E AN C by definition of intersection, and, in addition, x € B. Therefore x € (A N C) – B by the definition of set difference. By definition of set difference, x E A - B and x E C - B. By definition of intersection, x E A and x €B and x E C and x € B. By definition of intersection, x E A - B and x E C - B. By definition of set difference, x E A and x É B and x E C and x € B. To prove Part 1, select sentences from the list and put them in the correct order. 1. Suppose x E (A – B) N (C - B). 2. --Select--- 3. --Select-- 4. --Select--- 5. --Select-- 6. Hence, (A – B) N (C – B) S (A N C) – B by definition of subset. Part 2: Proof that (A N C) – BC (A – B) N (C – B) Consider the sentences in the following scrambled list. By definition of intersection, x € (A – B) (C – B). By definition of intersection x € A NC and x ¢ B. By definition of set difference, x E A and x E C. By definition of set difference x E ANC and x € B. Hence both xE A and x € B and also x E C, and x ¢ B. So by definition of set difference, x E A – B and x E C - B. Thus, by definition of intersection, x E A and x € C, and, in addition, x € B. To prove Part 2, select sentences from the list and put them in the correct order. 1. Suppose x E (A N C) – B. 2. --Select--- 3. -Select--- 4. --Select--- 5. ---Select- 6. ---Select--- 7. Hence, (A n c) - BC (A – B) N (C – B) by definition of subset.
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