To whomever keeps answering this: I appreciate the answers you’ve already given, but could you (or someone else) write the code using the options from the drop-down list shown in the second photo? Thank you!

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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To whomever keeps answering this: I appreciate the answers you’ve already given, but could you (or someone else) write the code using the options from the drop-down list shown in the second photo? Thank you!
LINE1
V [ Choose ]
if (s.length() == 0) {
if (s.charAt(0) == '0') {
LINE2
return countOnes(s.substring(0));
return '1';
if (s.length == 1) {
LINE3
if (s.length() :
1) {
} else {
if (s.charAt[0] == '0') {
LINE4
}
return "";
return 0;
LINE5
return countOnes(s.substring(1);
return 1+ countOnes(s.substring(1));
if (s.charAt(0) == '1') {
LINE6
{
return countOnes(s.substring(2));
if (s.length
== 0) {
LINE7
return 1+ countOnes(s.substring(2));
return '0';
return 1;
LINE8
return 1+ countOnes(s.substring(0));
if (s.charAt[0] == '1') {
Transcribed Image Text:LINE1 V [ Choose ] if (s.length() == 0) { if (s.charAt(0) == '0') { LINE2 return countOnes(s.substring(0)); return '1'; if (s.length == 1) { LINE3 if (s.length() : 1) { } else { if (s.charAt[0] == '0') { LINE4 } return ""; return 0; LINE5 return countOnes(s.substring(1); return 1+ countOnes(s.substring(1)); if (s.charAt(0) == '1') { LINE6 { return countOnes(s.substring(2)); if (s.length == 0) { LINE7 return 1+ countOnes(s.substring(2)); return '0'; return 1; LINE8 return 1+ countOnes(s.substring(0)); if (s.charAt[0] == '1') {
Counting the number of 1 bits in a bit string s can be accomplished in Java by first initializing an
integer counter n to 0. Next, we implement a loop which iterates over each character c of s and
when c is '1' we add 1 to n. When c is '0' we do nothing. Here is the implementation of that
algorithm:
private int countOnes(String s) {
int n = 0;
for (int i = 0; i < s.length(); ++i) {
if (s.charAt(i) == '1') {
++n;
}
return n;
This problem is also amenable to being solved using a recursive method rather than an iterative
method (one that employs a loop). Your job is to select the correct pieces of code from those
available and arrange them in proper order to implement a recursive method with the same method
signature.
private int countOnes(String s) {
[LINE1]
[LINE2]
[LINE3]
[LINE4]
[LINE5]
[LINE6]
[LINE7]
[LINE8]
[LINE9]
}
Transcribed Image Text:Counting the number of 1 bits in a bit string s can be accomplished in Java by first initializing an integer counter n to 0. Next, we implement a loop which iterates over each character c of s and when c is '1' we add 1 to n. When c is '0' we do nothing. Here is the implementation of that algorithm: private int countOnes(String s) { int n = 0; for (int i = 0; i < s.length(); ++i) { if (s.charAt(i) == '1') { ++n; } return n; This problem is also amenable to being solved using a recursive method rather than an iterative method (one that employs a loop). Your job is to select the correct pieces of code from those available and arrange them in proper order to implement a recursive method with the same method signature. private int countOnes(String s) { [LINE1] [LINE2] [LINE3] [LINE4] [LINE5] [LINE6] [LINE7] [LINE8] [LINE9] }
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