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Q: Transcribe in digital format the following text
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A: BELOW ? COMPLETE SOLUTION REGARDING YOUR PROBLEM :
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A: The question has been answered in step2
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A: The code is given in the below step
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A: Dear Student, the answer is provided below.
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Q: What is NAT? How can NAT help in address depletion?
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- The sieve of Eratosthenes is a way of computing all the prime numbers below a certain number. (A prime number is a number that is only divisible by itself and 1). This algorithm is explained excellently in this video (Links to an external site.), or you can read about this ancient algorithm on Wikipedia (Links to an external site.). In python, implement this algorithm: Implement a function cross_out_multiples that takes as arguments a list of boolean values (true/false) called is_prime and a number n. The function sets the boolean values at all multiples of n (2*n, 3*n, 4*n ...) that are in the list to false. Implement a function sieve(n) which gives back a list of all primes below n. See template code attached.Write a program called Super_Digit.java with a recursive function called superDigit. The function must return the calculated super digit as an integer. If 'x' has only 1 digit, then its super digit is 'x' Otherwise, the super digit of 'x' is equal to the super digit of the sum of the digits of 'x' Hint: use a combination of n%10 and n/10 The output should look like what is given below. Please give an editable code.Write a Java function that counts the number of 'x's in the string. Any 'x' that is followed by another 'x' should count double (e.g. "axxbxc" -> 4) /** * Count the number of 'x's in the string. Any 'x' that is followed by * another 'x' should count double (e.g. "axxbxc" -> 4) * * @param x a string. * @return the count of x's. */ public static int countXWithDubs(String s){ return -1; }
- What will be the space complexity of the following function?public static double test (int n){double x;if (n == 0) return 1.0;else{x = 0.0;for (int i = 0; i < n; i++)x += test(i);return x;}}A. O(1)B. O(n)C. O(2^n)D. O(n!)Write a function sum_of_digits(a,b), that takes two arguments a and b, computes a to the power of b, then recursively finds the sum of digits until there is only one digit left. You must PRINT all steps of the process as shown in the below example. sum_of_digits(5,3) will PRINT on the screen the following: 5ˆ3 = 125 = 1 + 2 + 5 = 8 sum_of_digits(2,8) will PRINT on the screen the following: 2ˆ8 = 256 = 2 + 5 + 6 = 13 = 1 + 3 = 4The sieve of Eratosthenes is a way of computing all the prime numbers below a certain number. (A prime number is a number that is only divisible by itself and 1). This algorithm is explained excellently in this video (Links to an external site.), or you can read about this ancient algorithm on Wikipedia (Links to an external site.). Implement this algorithm: Implement a function cross_out_multiples that takes as arguments a list of boolean values (true/false) called is_prime and a number n. The function sets the boolean values at all multiples of n (2*n, 3*n, 4*n ...) that are in the list to false. Implement a function sieve(n) which gives back a list of all primes below n. Needs to written in Python with the use of funtions and input parcers
- Use Python Write a function, print_integers_less_than(n), which takes an integer parameter n and prints each integer k which is at least 0 and is less than n, in ascending order. Hint: use a simple for loop. For example: Test Result print_integers_less_than(2) 0 1 print_integers_less_than(5) 0 1 2 3 4 print_integers_less_than(-3)Given an array of strings strs, group the anagrams together. You can return the answer in any order. An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once. Example 1: Input: strs = ["eat","tea","tan","ate","nat","bat"] Output: [["bat"],["nat","tan"],["ate","eat","tea"]] Example 2: Input: strs = [""] Output: [[""]].Write a recursive function to convert a given string into the number it represents. That is input will be a numeric string that contains only numbers, you need to convert the string into corresponding integer and return the answer. Input format : Numeric string S (string, Eg. "1234") Output format : Corresponding integer N (int, Eg. 1234) Constraints : 0 <= |S| <= 9 where |S| represents length of string S. Sample Input 1 : 00001231 Sample Output 1 : 1231 Sample Input 2 : 12567 Sample Output 2 : 12567 Solution:////////////////.
- int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *pLanguage: C Pascal’s triangle is a triangular array, useful for calculating the binomial coefficients, n k , that are used in expanding binomials raised to powers, combinatorics and probability theory. 0 0 1 0 1 1 2 0 2 1 2 2 3 0 3 1 3 2 3 3 4 0 4 1 4 2 4 3 4 4 Evaluating the values of the binomial coefficients, you get the following pattern, 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 The number of the entries in each row is increased by one, as we move down. Each number in the triangle, is constructed by adding the number above it and to the left, with the number above it and to the right. The blank entries as treated as 0. Using the recursion, implement the function that computes the Pascal’s triangle. PrWrite a program that takes in an integer in the range 20-98 as input. The output is a countdown starting from the integer, and stopping when both output digits are identical. Ex: If the input is 93, the output is: 93 92 91 90 89 88 Ex: If the input is 77, the output is: 77 Ex: If the input is not between 20 and 98 (inclusive), the output is: Input must be 20-98 For coding simplicity, follow each output number by a space, even the last one. Use a while loop. Compare the digits; do not write a large if-else for all possible same-digit numbers (11, 22, 33, ..., 88), as that approach would be cumbersome for large ranges.