Topic: Basic Formulas Used in Steel Design: (Allowable Stress Design) ASD Problem: A simple beam has a span of 10m and supports a superimposed uniformly distributed load of 20 kN/m. Properties of W450x70 A = 8700 mm² bf = 150 mm tf = 15 mm d =450 mm Ix = 274.7 x10⁶ mm⁴ Iy = 8.47 x106 mm⁴ tw = 10 mm Wb = 70 kg/m a. What is the average shearing stress in the beam? b. Determine the maximum shearing stress in the beam. c. Calculate the maximum bending stress in the beam.
Topic: Basic Formulas Used in Steel Design: (Allowable Stress Design) ASD Problem: A simple beam has a span of 10m and supports a superimposed uniformly distributed load of 20 kN/m. Properties of W450x70 A = 8700 mm² bf = 150 mm tf = 15 mm d =450 mm Ix = 274.7 x10⁶ mm⁴ Iy = 8.47 x106 mm⁴ tw = 10 mm Wb = 70 kg/m a. What is the average shearing stress in the beam? b. Determine the maximum shearing stress in the beam. c. Calculate the maximum bending stress in the beam.
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter12: Electric Current And Related Variables In Engineering
Section12.2: Electrical Circuits And Components
Problem 6BYG
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Topic: Basic Formulas Used in Steel Design: (Allowable Stress Design)
ASD
Problem: A simple beam has a span of 10m and supports a superimposed uniformly
distributed load of 20 kN/m.
Properties of W450x70
A = 8700 mm²
bf = 150 mm
tf = 15 mm
d =450 mm
Ix = 274.7 x10⁶ mm⁴
Iy = 8.47 x106 mm⁴
tw = 10 mm
Wb = 70 kg/m
a. What is the average shearing stress in the beam?
b. Determine the maximum shearing stress in the beam.
c. Calculate the maximum bending stress in the beam.
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