Treatments Error k-1 =3 N-k=716 SSTR = 212.9379 SSE 1,969.4932 MSTR = MSE = SSTr k-1 212.9379 SSE N-k 1,969.4932

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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Now that the degrees of freedom and sum of squares columns have been determined, we can calculate the values in the mean square column. Calculate the mean square for treatments, MSTr, and mean square for error, MSE,
and place them in the ANOVA table, rounding the results to three decimal places.
Degrees of Freedom
Source of Variation
Treatments
Error
k - 1 = 3
N - k = 716
Sum of Squares
SSTR = 212.9379
SSE = 1,969.4932
Mean Square
MSTR =
=
MSE =
SSTr
k - 1
212.9379
SSE
N-K
1,969.4932
F
Transcribed Image Text:Now that the degrees of freedom and sum of squares columns have been determined, we can calculate the values in the mean square column. Calculate the mean square for treatments, MSTr, and mean square for error, MSE, and place them in the ANOVA table, rounding the results to three decimal places. Degrees of Freedom Source of Variation Treatments Error k - 1 = 3 N - k = 716 Sum of Squares SSTR = 212.9379 SSE = 1,969.4932 Mean Square MSTR = = MSE = SSTr k - 1 212.9379 SSE N-K 1,969.4932 F
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