True or false. The last step for solving the longest common subsequences problem while using dynamic programing is to extract a lcs from the DP table. if we modify it by changing the order of the three cases as follow (case line 2-4 has been swapped with the case in line 7-8), it will still be able to output a lcs correctly. The last step for solving the Longest Common Subsequence (LCS) problem usingdynamic programming is to extract a LCS from the DP table (array L). Consider thePrint-LCS procedure discussed in class. If we modify it by changing the order ofthe three cases as follows (the case in lines 2-4 has been swapped with the case inlines 7-8), it will still be able to output a LCS correctly.Print-LCS (L, X, Y, m, n)if m > 0 or n > 02if L[m, n]L[m - 1, n - 1] + 1==Print-LCS (L, X, Y, m - 1, n - 1)4Print (X[m])5else if L[m, n] == L[m, n - 1]Print-LCS (L, X, Y, m, n1)7else8Print-LCS (L, X, Y, m - 1, n)TrueFalseLO

The program will find the longest common sub sequence. It is finding the longest common subset…

Answered: True or false. The last step for…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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True or false. The last step for solving the longest common subsequences problem while using dynamic programing is to extract a lcs from the DP table. if we modify it by changing the order of the three cases as follow (case line 2-4 has been swapped with the case in line 7-8), it will still be able to output a lcs correctly.