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Tutorial Exercise Find the linear approximation of the function g(x) 1 + x at a 0. Use it to approximate the numbers 0.95 and 1.1. Use technology to graph g and the tangent line in the same viewing window. Step 1 Recall that the linearization of g(x) for x = a is given by L(x) = g(a) + g'(a)(x-a). The first step is to find g'(x) so that it can be used to find g'(a). 1/9 1 + x = (1 + x) ¹/⁹, we have 1 For g(x) = g'(x) = (1 + x) Therefore, at a = 0 we have g'(0) = Submit 19 = Skin (you cannot come back)

Tutorial Exercise Find the linear approximation of the function g(x) 1 + x at a 0. Use it to approximate the numbers 0.95 and 1.1. Use technology to graph g and the tangent line in the same viewing window. Step 1 Recall that the linearization of g(x) for x = a is given by L(x) = g(a) + g'(a)(x-a). The first step is to find g'(x) so that it can be used to find g'(a). 1/9 1 + x = (1 + x) ¹/⁹, we have 1 For g(x) = g'(x) = (1 + x) Therefore, at a = 0 we have g'(0) = Submit 19 = Skin (you cannot come back)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 44E
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Tutorial Exercise Find the linear approximation of the function g(x) = 1 + x at a = 0. Use it to approximate the numbers 0.95 and 1.1. Use technology to graph g and the tangent line in the same viewing window. Step 1 Recall that the linearization of g(x) for x = a is given by L(x) = g(a) + g'(a)(x − a). The first step is to find g'(x) so that it can be used to find g'(a). For g(x) g'(x) = = Submit √1 + x = 1 (1+x) 1/9, we have (1 + x) Therefore, at a = 0 we have g'(0) = I /9 Skip (you cannot come back)
Transcribed Image Text:Tutorial Exercise Find the linear approximation of the function g(x) = 1 + x at a = 0. Use it to approximate the numbers 0.95 and 1.1. Use technology to graph g and the tangent line in the same viewing window. Step 1 Recall that the linearization of g(x) for x = a is given by L(x) = g(a) + g'(a)(x − a). The first step is to find g'(x) so that it can be used to find g'(a). For g(x) g'(x) = = Submit √1 + x = 1 (1+x) 1/9, we have (1 + x) Therefore, at a = 0 we have g'(0) = I /9 Skip (you cannot come back)
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