Tutorial Exercise Find the value of the derivative (If It exists) at the Indicated extremum. (475) f(x)=-3x√x+2 Step 1 -4 -2 10 5 -5 -10 2 The minimum and maximum of a function on an interval are the extreme values, or extrema (the singular form of extrema is extremum), of the function on the Interval. In the given problem, the extremum occurs when x = The specified function is f(x) = -3x√√x + 2 = −3x(x + 2)¹/2 Differentiate f(x) using the product rule. f'(x) = -3x| ~ + (x + 2)²/2-(

College Algebra
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ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.2: Domain And Range
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Tutorial Exercise
Find the value of the derivative (If It exists) at the Indicated extremum.
(= 4√6)
f(x) = -3x√x + 2
Step 1
The minimum and maximum of a function on an interval are the extreme values,
-5
The specified function is f(x) = -3x√√x + 2 = −3x(x + 2) ¹/2.
Differentiate f(x) using the product rule.
f'(x) = -3x
Submit
Skip (you cannot come back)
(x + 2)
+ (x+2) ¹/2-(
extrema (the singular form of extrema is extremum), of the function on the Interval. In the given problem, the extremum occurs when x =
Transcribed Image Text:Tutorial Exercise Find the value of the derivative (If It exists) at the Indicated extremum. (= 4√6) f(x) = -3x√x + 2 Step 1 The minimum and maximum of a function on an interval are the extreme values, -5 The specified function is f(x) = -3x√√x + 2 = −3x(x + 2) ¹/2. Differentiate f(x) using the product rule. f'(x) = -3x Submit Skip (you cannot come back) (x + 2) + (x+2) ¹/2-( extrema (the singular form of extrema is extremum), of the function on the Interval. In the given problem, the extremum occurs when x =
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