Tutorial Exercise Solve the differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition. Jry = 2x 4 Step 1 The first step is to rewrite the equation with the differential as y2Y = 2x. Now, separate the variables with all functions of y (including the differential dy) alone on one side of the equation and the constant and all functions of x (including dx) on the pther side. Doing this, we get dx y? dy = 2x dx. 2x Step 2 Next, we integrate both sides of our equation using the Power Rule. 2x dx + C

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Tutorial Exercise
Solve the differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition.
Sv²y = 2x
= 4
Step 1
The first step is to rewrite the equation with the differential as y2Y = 2x. Now, separate the variables with all functions of y (including the
differential dy) alone on one side of the equation and the constant and all functions of x (including dx) on the pther side. Doing this, we get
dx
y² dy = 2x
dx.
2x
Step 2
Next, we integrate both sides of our equation using the Power Rule.
2x dx
+ C
Transcribed Image Text:Tutorial Exercise Solve the differential equation and initial condition and verify that your answer satisfies both the differential equation and the initial condition. Sv²y = 2x = 4 Step 1 The first step is to rewrite the equation with the differential as y2Y = 2x. Now, separate the variables with all functions of y (including the differential dy) alone on one side of the equation and the constant and all functions of x (including dx) on the pther side. Doing this, we get dx y² dy = 2x dx. 2x Step 2 Next, we integrate both sides of our equation using the Power Rule. 2x dx + C
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