TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streaming is gaining inpopularity. A poll reported that 54% of 2342 American adults surveyed said they have watched digitally streamed TV programming on some typeof device.(a) Calculate and interpret a confidence interval at the 99% confidence level for the proportion of all adult Americans who watched streamedprogramming up to that point in time. (Round your answers to three decimal places.)Interpret the resulting interval.o We are 99% confident that the true population proportion lies below this interval.O We are 99% confident that the true population proportion lies above this interval.o We are 99% confident that this interval does not contain the true population proportion.We are 99% confident that this interval contains the true population proportion.(b) What sample size would be required for the width of a 99% CI to be at most 0.06 irrespective of the value of p? (Round your answer up tothe nearest integer.)

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Answered: TV advertising agencies face increasing…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The drug Viagra became available in the U.S. in May 1988, in the wake of an advertising campaign that was unprecedented in scope and intensity. A Gallup poll found that by the end of the first week of May, 643 out of 1,005 adults were aware that Viagra was an impotency medication. a) Is the sample size large enough to compute a confidence interval for the proportion of adults who were aware that Viagra was an impotency medication after the first week of May? Yes, because more than 10 adults were not aware of Viagra Yes, because the sample size is greater than 30 Yes, because more than 10 adults were aware of Viagra Yes, because both np̂ and n(1-p̂) are greater than 10 b)Using the information from questions 1-3, suppose that p̂ is 0.40 and the standard error of p̂ is 0.10. Compute a 90% confidence interval for the proportion of adults that were aware of Viagra. (0.2355, 0.5645) (0.3, 0.5) (0.2355, 0.4) (0.3, 0.4)
A research group studying cell phone habits asked the question “Do you ever use your cell phone to make a payment at a convenience store?” to people selected from two random samples of cell phone users. One sample consisted of older adults, ages 35 years and older, and the other sample consisted of younger adults, ages 18 years to 34 years. The proportion of people who answered yes in each sample was used to create a 95 percent confidence interval of (0.097,0.125)(0.097,0.125) to estimate the difference (younger minus older) between the population proportions of people who would answer yes to the question. Which of the following is the best description of what is meant by 95 percent confidence? In repeated random sampling with the same sample size, approximately 95% of the sample proportions from the younger group will be between 0.097 and 0.125 greater than the sample proportion from the older group. A In repeated random sampling with the same sample size,…
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streaming is gaining in popularity. The Harris poll reported on November 13, 2012, that 53% of 2343 American adults surveyed said they have watched digitally streamed TV programming on some type of device.a. Calculate and interpret a confidence interval at the 99% confidence level for the proportion of all adult Americans who watched streamed programming up to that point in time.b. What sample size would be required for the width of a 99% CI to be at most .05 irrespective of the value of p
A November 2018 CBS News Poll found that 35% of its sample planned to use online retailers for most holiday shopping. Give a 95% confidence interval for the proportion of all adults who plan to shop in this way, assuming that the result ˆp=0.35 comes from a sample size n= 650 n=1800 n=500 Explain briefly what your results show about the effect of increasing the size of a sample on the width of the confidence interval.
Are nursing salaries in Tampa, Florida, lower than those in Dallas, Texas? Salary data show staff nurses in Tampa earn less than staff nurses in Dallas (The Tampa Tribune, January 15, 2007). Suppose that in a follow-up study of 40 staff nurses in Tampa and 50 staff nurses in Dallas you obtain the following results. Tampa n1 = 40 X1 = $56,100 S1 = $6000 Dallas n2 = 50 X2 = $59,400 S2 = $7000 Complete the confidence interval of the data set
A recent study on the way that people talk indicated, with 95 percent confidence, that between 35 percent and 41percent of all adults find the word “whatever” to be the most annoying word in conversation.Based on the confidence interval, which of the following claims is supported?(A) Less than 25 percent of all adults find the word “whatever” to be the most annoying word in conversation.(B) More than 30 percent of all adults find the word “whatever” to be the most annoying word in conversation.(C) More than 45 percent of all adults find the word “whatever” to be the most annoying word in conversation.(D) More than half of all adults find the word “whatever” to be the most annoying word in conversation.(E) At least 95 percent of all adults find the word “whatever” to be the most annoying word in conversation.
With the growth of internet service providers, a researcher decides to examine whether there is a correlation between cost of internet service per month (rounded to the nearest peso) and degree of customer satisfaction (on a scale of 10 - 100 with a 10 being not at all satisfied and a 100 being extremely satisfied). The researcher only includes programs with comparable types of services. A sample of the data is provided below. f. At 95% Confidence Level, construct a Confidence and Prediction Interval for your answer in (d). Blank 7 < y < Blank 8 Blank 9 < y(n+1) < Blank 10
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and the United Kingdom. They found that a substantially greater percentage of U.K. ads use humor.a. Suppose that a random sample of 400 television ads in the United Kingdom reveals that 142 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.K. television ads that use humor.b. Suppose a random sample of 500 television ads in the United States reveals that 122 of these ads use humor. Find a point estimate of and a 95 percent confidence interval for the proportion of all U.S. television ads that use humor.c. Do the confidence intervals you computed in parts a and b suggest that a greater percentage of U.K. ads use humor? Explain.
After reporting the results from a formal hypothesis test, it is often likely that statisticians will report a confidence interval in order to indicate that a null value is present, indicating a significant response . True False
Gallup is a company that conducts daily opinion polls on a variety of topics. In a recent daily survey of 1,000 randomly selected adults in the United States, 38% of the sample said they were committed to their work. Based on this sample, which of the following is a 97% confidence interval for the proportion of all adults in the United States who would say they are engaged in their work? Select one: a. (0.347, 0.413) b. (0.319, 0.441) c. (0.350, 0.410) d. (0.365, 0.395) e (0.340, 0.420)
A pew Poll conducted in 2013 surveyed a random sample of 2003 adult Americans, and 18% of them said that they had seen a ghost. a) Find the standard error. b) Find an approximate 90% confidence interval for the percentage of all Americans who believe they have seen a ghost. c) Is it plausible to conclude that 25% or more Americans believe they have seen a ghost?
A farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to yield marketable strawberries. Of a random sample of 100 blooms,77 yield marketable strawberries. Is this evidence that two thirds or more of all blooms grown with this pest control method end up as marketable strawberries? The 95%large-sample confidence interval for the proportion of blooms that yield marketable strawberries is: A. 0.77± 0.042 B. 0.77±0.082 C. 0.77±0.0034 D. 0.77±0.0017G5

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