Question
Asked Oct 6, 2019
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Twice the length of a rectangle is equal to four times its width. The perimeter of a rectangle is 80 inches. Find the dimensions of the rectangle.

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Expert Answer

Step 1

Let l and w be the length and width of the rectangle, respectively.

Given that, twice the length of a rectangle is equal to four times its width. That is,

21 4w
..1)
l 2w
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21 4w ..1) l 2w

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Step 2

Given that, the perimeter of a rect...

2w)80
2/ 2w 80
( 21 4w)
4w 2w 80
6w 80
80
w
6
40
or w=13
3
3
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2w)80 2/ 2w 80 ( 21 4w) 4w 2w 80 6w 80 80 w 6 40 or w=13 3 3

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