Two 20-mm steel plates are butt-welded together. Both the plate and the welding = 500 MPa and electrode materials correspond to strength properties of Su S₁ = = 400 MPa. The imposed loading fluctuates rapidly between -20 and +60 kN. Estimate the length of weld required in order to provide a safety factor of 2.5: (a) If the weld reinforcement is not removed. (b) If the excess weld material is carefully ground off to provide smooth, continu- ous surfaces.
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- Te - Effective throat thickness well in mm = 6 sin45° Consider the following drawing in which plate 1 is welded onto plate 2 as shown for tensile and shear loading. The plates are fillet welded with a weld thickness of 6 mm as shown for a length of 150 mm. The plates have an ultimate strength of 275 MPa and the welding was done with F70 welding electrodes, which possesses an ultimate strength of 483 MPa. Consider a partial factor of safety of 1.7 for the welded joint and determine the design strength of the weld joint, both in tension (Tdw) and in shear (Vdw) due to the forces acting on it. a) Determine the design strength of the following weld in tension ( ) due to vertical forces. b) Determine the design strength of the weld in shear ( ) due to horizontal forces. Attached pic is shear equation for calculation Tension equation for calculation is: Tdw = FyLwte /YmwA mild steel ammonia receiver is a cylinder 2 m in diameter with a pressure load of 1250 kPa and a design stress of 65 MPa. The lap welding tensile strength is 450 MPa and the weld -joint efficiency is assumed to be 100%. Compute the bursting pressure of the receiver in kN/m².A GTAW operation is performed on low carbon steel, whose unit melting energy is 10.3 J/mm3. The welding voltage is 22 volts and the current is 135 amps. The heat transfer factor is 0.7 and the melting factor is 0.65. If filler metal wire of 3.5 mm diameter is added to the operation, the final weld bead is composed of 60% volume of filler and 40% volume base metal. If the travel speed in the operation is 5 mm/sec, determine (a) cross-sectional area of the weld bead, and (b) the feed rate (mm/sec) at which the filler wire must be supplied.
- A cylindrical air-compressor tank with an inside diameter of 50 mm is to be designed to withstand safely a working pressure of 0.86 MPa. Boiler plate with an allowable tensile stress of 76 MPa. All seams will be butt welds with an expected efficiency of 100 percent. a.) Determine the force per lineal mm of longitudinal seam, b.) Determine the required thickness “t” of wall, c.) Determine the unit stress in the circumferential seam.An RSW operation is used to join two pieces of sheet steel having a unit melting energy of 8369.85 J/cm3. The sheet steel has a thickness of 0.3125 cm. The weld duration will be set at 0.25 sec with a current of 11,000 amp. Based on the electrode diameter, the weld nugget will have a diameter of 0.75 cm. Experience has shown that 40% of the supplied heat melts the nugget and the rest is dissipated by the metal. If the electrical resistance between the surfaces is 130 micro-ohms, what is the thickness of the weld nugget assuming it has a uniform thickness?a) list two advantages and two disadvantages of welded joints b) Name the type of bonding forces applied in welded joints A plate 50mm wide by 11mm thick is joined with another plate 120mm wide by 11mm thick by parallel welds of 40mm long.if the permissible tensile and shear stresses are 110MPa and 80MPa respectively calculate; i) safe load F carried by the joint ii) Efficiency of the joint
- Dynamic forces F1 = 4000N and F2 = 6000N are applied to the welded part shown in the figure as shown below. For dynamic forces, both dynamics are synchronized, and when the force in the y-axis direction is downward, it is on the right in the x-axis direction. When the force is up, the other force is on the left. The welded part is made of 1018 HR steel, 10 mm thick. a) Safety factor for welding? b) Calculate the safety factor for the base metal. (Electrode type for question is E9010.)A bracket to be welded into a steel channel using E-60 electrode 345 Mpa) Two welding sets are suggested as shown in Fig. (1)Based on maximum shear stress failure theory and safety factor of (2.5) (a) Find the weld size for each set. (b) Which set would you recommend A or B ?The unit melting energy for a certain sheet metal is 10J/mm^3 .The thickness of each of the two sheets to be spot-welded is = mm. To achive required strength, it is desired to form a weldnugget that is =7 mm in diameter and 3.5 mm thick. The weld duration will be set at 44 sec .If the electrical resistance between the two surfaces is 144 micro-ohms and only one half the electricity generated will be used to form the weld nugget Determine the minium current level required in this operation
- Question: a) A plate 100 mm wide and 10 mm thick is to be welded to another plate by means of double parallel fillets. The plates are subjected to a static load of 80 kN. Find the length of weld if the permissible shear stress in the weld does not exceed 55MPa. Determine the increase in load carrying capacity if a combination of single transverse double parallel fillet is used the permissible tensile strength of material is 80MPa. b) Draw a neat sketch of double riveted double cover but joint. If 8mm plates with 20 mm diameter rivets having a pitch of 50 mm are joint using double riveted lap joint. The permissible stresses are permissible tensile stress = 120 MPa;Permissible crushing stress= 100 MPa; Permissble shear stess= 150 MPa. Find the strengths and efficiency of joint, taking the strength of the rivet in double shear acoording to the indian boiler standards.An angle iron made of AISI 1040 CD steel is welded to metal as shown and loaded with a dynamic load varying between +40kN and +60kN. E70XX (Sut = 482MPa, Sy = 393MPa) will be used as the welding electrode. Find the factor of safety of the weld zone. Note: that both static and dynamic loads are applied to the source.A U-groove weld is used to butt weld 2 pieces of 7.0-mm-thick titanium plate. The U-groove is prepared using a milling cutter so the radius of the groove is 3.0 mm. During welding, the penetration of the weld causes an additional 1.5 mm of material to be melted. The final cross-sectional area of the weld can be approximated by a semicircle with a radius of 4.5 mm. The length of the weld is 200 mm. The melting factor of the setup is 0.57 and the heat transfer factor is 0.86. (a) What is the quantity of heat (in Joules) required to melt the volume of metal in this weld (filler metal plus base metal)? Assume the resulting top surface of the weld bead is flush with the top surface of the plates. (b) What is the required heat generated at the welding source?