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Two cyclists leave towns 144 km apart at the same time and travel toward each other. One cyclist travels 6 km/h faster than the other. If they meet in 3 hours,what is the rate of each cyclist?

Question
Two cyclists leave towns 144 km apart at the same time and travel toward each other. One cyclist travels 6 km/h faster than the other. If they meet in 3 hours,
what is the rate of each cyclist?
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Two cyclists leave towns 144 km apart at the same time and travel toward each other. One cyclist travels 6 km/h faster than the other. If they meet in 3 hours, what is the rate of each cyclist?

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Step 1

 Given that two cyclist 114 km apart travel each other at same time one cyclist travel 6 km/h faster than the other, they meet in 3 hours.

Let the speed of one cyclist be x km/h.

Then the speed of other cyclist will be (x+6)km/h.

Since both of them meet each other after 3 hours.

Step 2

Formula to calculate distance is given by,

Distance speed x time
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Distance speed x time

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Step 3

The distance travelled ...

D xx3
= 3x
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D xx3 = 3x

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Tagged in

Math

Algebra

Numbers

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