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Two diodes are connected in series as shown in Figure 2.11a to share a total de reverse volt age of VD=5 KV. The reverse leakage currents of two diode I=25 mA, 1,2 = 30 mA. (a) Find the diode voltage if the voltage sharing resistances R₁ and R₂ are equal R₁ = R₂ = 200 KN. (b) Find the voltage sharing resistance R₁ and R₂ if the diode voltage are equal Vd1= Vd2= Vd/2

Two diodes are connected in series as shown in Figure 2.11a to share a total de reverse volt age of VD=5 KV. The reverse leakage currents of two diode I=25 mA, 1,2 = 30 mA. (a) Find the diode voltage if the voltage sharing resistances R₁ and R₂ are equal R₁ = R₂ = 200 KN. (b) Find the voltage sharing resistance R₁ and R₂ if the diode voltage are equal Vd1= Vd2= Vd/2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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2.13 Two diodes are connected in series as shown in Figure 2.11a to share a total de reverse volt age of VD=5 KV. The reverse leakage currents of two diode I=25 mA, 1,2 = 30 mA. (a) Find the diode voltage if the voltage sharing resistances R₁ and R₂ are equal R₁ = R₂ = 200 KN. (b) Find the voltage sharing resistance R₁ and R₂ if the diode voltage are equal Vd1= Vd2= Vd/2   

www D₁ D₂ w R₂ (a) Steady state + op
Transcribed Image Text:www D₁ D₂ w R₂ (a) Steady state + op
2200 FIGURE P2.6 2000 1600 1200 800 150 100 400 200 50 ·+· 0.5 1.0 2 5 mA 10 mA 15 mA -20 mA 25 mA L 30 mA 3
Transcribed Image Text:2200 FIGURE P2.6 2000 1600 1200 800 150 100 400 200 50 ·+· 0.5 1.0 2 5 mA 10 mA 15 mA -20 mA 25 mA L 30 mA 3
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