Two solid shafts of different materials are rigidly fastened together and attached to rigid supports as shown. The aluminum segment is 3 inches in diameter and G = 4 x 10^6 psi. The steel segment has a diameter of 2 inches and G = 12 x 10^6 psi. The torque, T = 10 kips.in. is applied at the junction of the two segments. Compute the maximum shearing stress developed in the assembly. 6 ft- 3 ft- Tal Aluminum Steel. C 3 in. dia. T = 10 kip in. 2 in. dia. G Gal = 4 x 106 psi 12x 106 psi Tst

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Two solid shafts of different materials are
rigidly fastened together and attached to rigid
supports as shown. The aluminum segment
is 3 inches in diameter and G = 4 x 10^6 psi.
The steel segment has a diameter of 2 inches
and G = 12 x 10^6 psi. The torque, T = 10
kips.in. is applied at the junction of the two
segments. Compute the maximum shearing
stress developed in the assembly.
6 ft-
3 ft-
Tal
CTSt
Aluminum
Steel
3 in. dia.
T = 10 kip in.
Gal = 4 x 106 psi
2 in. dia.
G
-
12 x 106 psi
Transcribed Image Text:Two solid shafts of different materials are rigidly fastened together and attached to rigid supports as shown. The aluminum segment is 3 inches in diameter and G = 4 x 10^6 psi. The steel segment has a diameter of 2 inches and G = 12 x 10^6 psi. The torque, T = 10 kips.in. is applied at the junction of the two segments. Compute the maximum shearing stress developed in the assembly. 6 ft- 3 ft- Tal CTSt Aluminum Steel 3 in. dia. T = 10 kip in. Gal = 4 x 106 psi 2 in. dia. G - 12 x 106 psi
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