Homework Help is Here – Start Your Trial Now!
Math
Advanced Math
Tx1 + 3x2 + 4x3 =7 (g) x1 + x2 + x3 + x4 = 0 %3D 2x1 + 3x2 – X3 – X4 = 2 3x1 + 2x2 + x3 + x4 = 5 3x1 + 6x2 – x3 – X4 = 4 %3D X1 – 2x2 = 3 2x1 + x2= 1 -5x1 + 8x2 = 4 (h) %3D (i) -2x1 + 2x2 + X3 = 4 3x1 + 2x2 + 2x3 = -x1 + 2x2 – x3 = 2 %3D %3D -3x1+ 8x2 + 5x3 = 17 () Xi + 2x2 – 3x3 + x4 = 1 -x1 - x2 + 4x3 – x4 = 6 -2x1 - – x4 = 1 - %3D 4x2 +7x3 (k) X1 + 3x2 + x3 + x4 = 3 %3D 2x1 – 2x2 + x3 + 2x4 = 8 X1-5x2 + X4 = 5 a list (1) X1 - 3x2 + X3 = 1 2x1 + x2 - X3= 2 free ollow, valent chelon ent. If X+4x2 - 2x3 = 1 8x2 + 2x3 5x1 6. Use Gauss-Jordan reduction to solve each of the following

Tx1 + 3x2 + 4x3 =7 (g) x1 + x2 + x3 + x4 = 0 %3D 2x1 + 3x2 – X3 – X4 = 2 3x1 + 2x2 + x3 + x4 = 5 3x1 + 6x2 – x3 – X4 = 4 %3D X1 – 2x2 = 3 2x1 + x2= 1 -5x1 + 8x2 = 4 (h) %3D (i) -2x1 + 2x2 + X3 = 4 3x1 + 2x2 + 2x3 = -x1 + 2x2 – x3 = 2 %3D %3D -3x1+ 8x2 + 5x3 = 17 () Xi + 2x2 – 3x3 + x4 = 1 -x1 - x2 + 4x3 – x4 = 6 -2x1 - – x4 = 1 - %3D 4x2 +7x3 (k) X1 + 3x2 + x3 + x4 = 3 %3D 2x1 – 2x2 + x3 + 2x4 = 8 X1-5x2 + X4 = 5 a list (1) X1 - 3x2 + X3 = 1 2x1 + x2 - X3= 2 free ollow, valent chelon ent. If X+4x2 - 2x3 = 1 8x2 + 2x3 5x1 6. Use Gauss-Jordan reduction to solve each of the following

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.2: Direct Methods For Solving Linear Systems
Problem 4CEXP
See similar textbooks
icon
Related questions
Question
100%
Both pictures are part of the same question. I only need 5g and 5 k. Thank you
of the lead Variables a second 1ist of variables. 5. For each of the systems of equations that follow, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in row echelon form. Indicate whether the system is consistent. If the system is consistent and involves no free vari- ables, use back substitution to find the unique solu- tion. If the system is consistent and there are free variables, transform it to reduced row echelon form and find all solutions. X1 – 2x2 = 3 2x1 – x2 =9 (a) (b) 2x1 – 3x2 = 5 -4x1 + 6x2 = 8 (c) X1 + x2 =0 2x1 + 3x2 = 0 3x1 – 2x2 = 0 (d) 3x1 + 2x2 - X3 = 4 X1 – 2x2 + 2x3 = 11x1 + 2x2 + 1 7. X3 = 14 (e) 2x1 + 3x2 + x3 =1 tF X1+ x2 x3 =3 tic 3x1 + 4x2 + 2x3 = 4 of geo FEB 14
Transcribed Image Text:of the lead Variables a second 1ist of variables. 5. For each of the systems of equations that follow, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in row echelon form. Indicate whether the system is consistent. If the system is consistent and involves no free vari- ables, use back substitution to find the unique solu- tion. If the system is consistent and there are free variables, transform it to reduced row echelon form and find all solutions. X1 – 2x2 = 3 2x1 – x2 =9 (a) (b) 2x1 – 3x2 = 5 -4x1 + 6x2 = 8 (c) X1 + x2 =0 2x1 + 3x2 = 0 3x1 – 2x2 = 0 (d) 3x1 + 2x2 - X3 = 4 X1 – 2x2 + 2x3 = 11x1 + 2x2 + 1 7. X3 = 14 (e) 2x1 + 3x2 + x3 =1 tF X1+ x2 x3 =3 tic 3x1 + 4x2 + 2x3 = 4 of geo FEB 14
(f) X1 - X2 + 2x3 = 4 2x1 + 3x2 - x3 = 1 7x1 + 3x2 + 4x3 = 7 (8) X1 + x2 + x3 + x4 = 0 2x1 + 3x2 – x3 – x4 = 2 3x1 + 2x2 + x3 + x4 = 5 3x1 + 6x2 – x3 – X4 = 4 X1 – 2x2 = 3 2x1 + x2 = 1 (h) -5x1 + 8x2 = 4 %3D (i) -x1 + 2x2 – x3 = 2 -2x1 + 2x2 + X3 = 4 3x1 + 2x2 + 2x3 = 5 -3x1 + 8x2 + 5x3 = 17 (j) X1 + 2x2 - 3x3 + x4 = 1 -x1 - X2 + 4x3 – x4 = 6 -2x1 - 4x2 +7x3 – x4 = 1 (k) X+3x2 + x3 + x4 = 3 2x1 - 2x2 + x3 + 2x4 = 8 X1 - 5x2 + X4 = 5 ke a list the free (1) X1-3x2 + X3 = 1 2x1 + x2 - X3 = 2 X1 + 4x2 – 2x3 = 1 5x1 - 8x2 + 2x3 = 5 at follow, equivalent w echelon nsistent. If o free vari- anique solu- еге агe free 6. Use Gauss-Jordan reduction to solve each of the following systems: Se (a) X1 + x2 = -1
Transcribed Image Text:(f) X1 - X2 + 2x3 = 4 2x1 + 3x2 - x3 = 1 7x1 + 3x2 + 4x3 = 7 (8) X1 + x2 + x3 + x4 = 0 2x1 + 3x2 – x3 – x4 = 2 3x1 + 2x2 + x3 + x4 = 5 3x1 + 6x2 – x3 – X4 = 4 X1 – 2x2 = 3 2x1 + x2 = 1 (h) -5x1 + 8x2 = 4 %3D (i) -x1 + 2x2 – x3 = 2 -2x1 + 2x2 + X3 = 4 3x1 + 2x2 + 2x3 = 5 -3x1 + 8x2 + 5x3 = 17 (j) X1 + 2x2 - 3x3 + x4 = 1 -x1 - X2 + 4x3 – x4 = 6 -2x1 - 4x2 +7x3 – x4 = 1 (k) X+3x2 + x3 + x4 = 3 2x1 - 2x2 + x3 + 2x4 = 8 X1 - 5x2 + X4 = 5 ke a list the free (1) X1-3x2 + X3 = 1 2x1 + x2 - X3 = 2 X1 + 4x2 – 2x3 = 1 5x1 - 8x2 + 2x3 = 5 at follow, equivalent w echelon nsistent. If o free vari- anique solu- еге агe free 6. Use Gauss-Jordan reduction to solve each of the following systems: Se (a) X1 + x2 = -1
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra for College Students
Algebra for College Students
Algebra
ISBN:
9781285195780
Author:
Jerome E. Kaufmann, Karen L. Schwitters
Publisher:
Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
SEE MORE TEXTBOOKS