uint16_t data = wiringPiI2CReadReg16(adc, 0x00); low = (data & 0xFF00) >> 8; high = (data & 0x00FF) << 8; value = (high | low)>>4; return value; I know this stables the value some how but how and why
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uint16_t data = wiringPiI2CReadReg16(adc, 0x00);
low = (data & 0xFF00) >> 8;
high = (data & 0x00FF) << 8;
value = (high | low)>>4;
return value;
I know this stables the value some how but how and why
Please give explanation
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Solved in 2 steps
- As a software engineer, you are hired to arrange cricket players based on their country and type. You have given all the player’s information in a tuple called my_tuple. The players are from 3 countries which are Bangladesh, Australia and England. There are 2 types of players which are “Batters” and “Bowlers”You are given the following nested tuple where each element in the my_tuple is a tuple consisting of a name and a 4 digit ID.my_tuple = (("Mominul", 1101),("Mustafiz", 1202),("Bell", 2101),("Cook", 2103),("Smith", 3101),("Finch", 3102),("Starc", 3203), ("Imrul", 1103), ("Taijul", 1204))Write a python program that will convert this tuple into the following dictionary using the process described below: Your code should work for all types of similar tuple if the sample input is changed.Output dictionary (You just have to print the resultant dictionary. No need to follow the pattern below){'Bangladesh': { 'Batters': ('Mominul', 'Imrul'), 'Bowlers': ('Mustafiz', 'Taijul')…The language used here is in Racket. Please explain what is the code doing and the meaning of each line. (define intersect(lambda (set1 set2)(cond((null? set1)(quote ()))((member (car set1) set2)(cons (car set1)(intersect (cdr set1) set2)))(else (intersect (cdr set1) set2))))) (intersect '(1 2 3) '(3 2 1))(intersect '(1 2 3) '(4 5 6))(intersect '(1 2 3) '(2 3 4 5 6))# Create Custom Transformer Create a custom transformer, just as we did in the lecture video entitled "Custom Transformers", that performs two computations: 1. Adds an attribute to the end of the numerical data (i.e. new last column) that is equal to $\frac{x_1^3}{x_5}$ for each observation. In other words, for each instance, you will cube the $x_1$ column and then divide by the $x_5$ column. 2. Drops the entire $x_4$ feature column if the passed function argument `drop_x4` is `True` and doesn't drop the column if `drop_x4` is `False`. (See further instructions below.) You must name your custom transformer class `Assignment4Transformer`. Your class should include an input parameter called `drop_x4` with a default value of `True` that deletes the $x_4$ feature column when its value is `True`, but preserves the $x_4$ feature column when you pass a value of `False`. This transformer will be used in a pipeline. In that pipeline, an imputer will be run *before* this transformer. Keep…
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- C++ Please explain the code below. It doesn't have to be long, as long as you explain what the important parts of the code do. You can also explain it line by line for best ratings. Thank you so much! The code is already correct, only explanation needed void addTail(int num) { node* newest = create_node(num); if (tail != NULL) { tail->next = newest; } tail = newest; if (head == NULL) { head = newest; } index++; } int add(int num) { addTail(num); return index; } int get(int pos) { node* currnode = head; int count = 0; while (currnode != NULL){ count++; if (count == pos){ return currnode -> element; }else{ currnode = currnode -> next; } } return -1; } int size() { return index; }…Racket (define (arg-max f a)(define (helper f a m v)(if (null? (car a)) v(if (> (f (car a)) m)(helper (f (car a)) (cdr a) (= m (f (car a))) (= v (car a)))(helper (f (car a)) (cdr a) m v))))(helper f a 0 (car a))) (define (square a) (* a a))> (arg-max square '(3 2)). . application: not a procedure;expected a procedure that can be applied to argumentsgiven: 9> I want to create a helper function to return the most argument a, but I find this error when debugging, the error is located in inner if condition '(> (f (car a)) m)'. My parameter f would be a function and has one parameter from list a. How can I modify my code? Thanks!./llcpInt.cpp:28:14: error: no viable overloaded '=' temp=headPtr; ~~~~^~~~~~~~./llcpInt.h:6:8: note: candidate function (the implicit copy assignment operator) not viable: no known conversion from 'Node *' to 'const Node' for 1st argument; dereference the argument with *struct Node ^./llcpInt.h:6:8: note: candidate function (the implicit move assignment operator) not viable: no known conversion from 'Node *' to 'Node' for 1st argument; dereference the argument with *struct Node ^./llcpInt.cpp:30:10: error: cannot delete expression of type 'Node' delete temp; ^ ~~~~./llcpInt.cpp:38:15: error: no viable overloaded '=' temp=currentNode->link; ~~~~^~~~~~~~~~~~~~~~~~./llcpInt.h:6:8: note: candidate function (the implicit copy assignment operator) not viable: no known conversion from 'Node *' to 'const Node' for 1st argument; dereference the argument with *struct Node ^./llcpInt.h:6:8: note: candidate function (the…
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