Question
Asked Oct 27, 2019
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Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π)
2 sin2(θ) = 2 + cos(2θ)

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Expert Answer

Step 1

Given,

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2 sin(20) 2+ cos(20) 1-tan2(e) 2 + 1+tan2(0) 2 tan e 2( 1-tan2 (e). 2+2tan2 (e)+1-tan2 (0) 1+tan2(e) 4 tan e 1+tan2 (e) 3+tan2(e) 4 tan e 1+tan2 (0) 1+tan2(e) 3tan2 (0) 4 tan 0 = tan2 (0) - 4 tan 0 +3 = 0 tan2 (0) - 3 tan 0 - tan0 3 = 0 tan 0 (tan 0 -3) 1(tan 0 - 3) 0 3)(tan 0 1) 0 (tan e Either tan 0 - 3 = 0 or tan 0 - 1 = 0 tan 0 3 or tan 0 1

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Step 2

Now,

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3 tan e tan(3) 1.249,1.249 + t = 1.249,4.39 ө Or 1 tan e п 5п tan (1) ө 4 4

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Tagged in

Math

Trigonometry

Trigonometric Ratios