Use a One-to-One Property to solve the equation e3x−5 = e7 for x.

Q: solve the equation for x. a(x+b)=c

A:

Q: For Exercise, solve the equation. 4 = 3 + 3(x + 1)

A: Given:

Q: Solve for the unknown variable. (b2)x+1 = b-6

A: The exponent of exponent multiplies

Q: Solve for the value of x: 18 A 5x-7

A: Use Pythagorean theorem.

Q: Solve the equation for x.  4ex . e-2x = 6

A: The given equation is 4ex.e-2x=6

Q: solve the equation. √(2x) = x - 4

A:

Q: Solve: e2x - 4ex + 3 = 0.

A:

Q: 2(*) 36 54 А 21 - A ||

A:

Q: First, solve the equation 160 =-5x² + 48x + 27 for x.

A:

Q: For Exercise, solve the equation. 2 (x + 1) + 10 ||

A: The given equation is

Q: Solve e a 10 + (b) -4х

A:

Q: Solve the equation by using a u-substitution: x 5 + x5-2=0

A: The given equation is: x25+x15-2=0⇒x152+x15-2=0

Q: Solve the equation. ex + 15e-x - 8 = 0

A: The given equation,  ex+15e-x-8=0. or it can write in the form, ex+151ex-8=0e2x+15-8ex=0…

Q: Solve e2+x=02

A: We have to solve the equation  :  e2+x=2

Q: Solve for the value of x: B. 18 5x-7 C.

A: So as we know that if two chords are equidistant from the centre of circld then both the chords are…

Q: For Exercise, solve the equation. V5 = 5'

A:

Q: solve the equation fo x. 5x=(3x-2)(m+4)

A:

Q: For Exercise, solve the equation. 50e2x+1 = 2000

A: Given: The equation

Q: 1 x-2 | 1 1 x-1 6 ||

A:

Q: Solve the equation. e2x - 3ex + 2 = 0

A: We have to solve the equation: e2x-3ex+2=0 Solving equation by middle term splitting method,…

Q: For Exercise, solve the equation. | 2p*/5

A: Given

Q: What value of x makes the equation -4+12x=8

A: SOLUTION-

Q: Solve the equation for x. 4x x =D15 17 X

A:

Q: Solve the equation. ​ x4 + 1,296 = 0

A:

Q: Solve the equation algebraically 2+ x 9 ||

A:

Q: For Exercise, solve the equation. V3 = 3"

A:

Q: Solve for the positive value of x that satisfies the following equation: (x + 20)(x - 5) = 350

A:

Q: Solve for x in e5x = 6    Answer only please

A: According to the definition of the logarithm, if  y=ax, then lnay=x. The number a is called the base…

Q: For Exercise, solve the equation. 2 &x – 3 2x + 5

A: We cross multiply

Q: solve the equation for x. 5x=(3x-2)(m+4)

A:

Q: Solve the equation. |x - 1| = |3x + 2|

A: Given equation: x-1=3x+2 Solve Absolute Value. x-1=3x+2 We know either x−1=3x+2 or x−1=−(3x+2)

Q: Solve the equation. x - {(2x + 4) 3 – 8) = 4 x =

A: Given- 34x-8=182x+4 To find- The value of  variable x.

Q: Solve the equation without using a calculator .

A: Given the equation is e2x+2ex-15 = 0 To solve the given equation Take u = ex ex2+2ex-15 = 0u2 + 2u -…

Q: Set up an equation and solve. A student has 8 liters of a 10% alcohol solution. How much pure…

A: Let x be the amount(in litres) pure alcohol the student should add.

Q: Solve for x the equation 4x - 2 = 3x + 4

A: To solve the given equation for x

Q: Determine the solution of the equation e0.5x – Jx = 3.

A:

Q: For Exercise, solve the equation. V4 – x – V2x + 1 = 0

A: Given equation

Q: Solve the equation for x: Vr -6 = -2

A:

Q: For Exercise, solve the equation. V2t + 8 – t= 4

A: Given equation:

Q: Solve the equation exactly for (0,2π)

A: Given trigonometric equation is:  Simplifying the equation,  Therefore,The solution to the given…

Q: Use the One-to-One Property to solve the equation for x. ex2-4  = e3x ​

A: Refer to the question,According to one to one property of exponents if bases are same, af(x) =…

Q: Solve the equation

A: To solve the equation: 6-s23+5=0. Solution: Solving the given equation. 6-s23+5=06-s23=-56-s233=-53…

Q: Solve the equation.

A: The given equation is x2+13x+2=0

Q: Solve the equation |4x- 3|=x.

A:

Q: solution

A:

Q: Solve the equation. x*+1,296 = 0

A: Topic- root of complex equation

Q: Solve for the variable: (-14/x2-x-12) - 1/x-4=2/x+3

A: Consider the given rational expression.

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.