Use base-ten blocks to illustrate 142 + 5. 142 has flat(s), long(s), and unit(s). Starting with the flats, there are set(s) of 5 flats with remaining. Converting the remaining flats to longs gives a total of long(s), which leads to set(s) of 5 longs with remaining. Converting the remaining longs to units gives a total of unit(s), which leads to set(s) of 5 units with remaining. Therefore, the quotient is with a remainder

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter2: The Integers
Section2.7: Introduction To Coding Theory (optional)
Problem 12E: Suppose that the check digit is computed as described in Example . Prove that transposition errors...
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Use base-ten blocks to illustrate 142 + 5.
142 has flat(s),
long(s), and
unit(s).
Starting with the flats, there are
set(s) of 5 flats with
remaining.
Converting the remaining flats to longs gives a total of
long(s), which leads to
set(s) of 5 longs with
remaining.
Converting the remaining longs to units gives a total of
unit(s), which leads to
set(s) of 5 units with
remaining.
Therefore, the quotient is
with a remainder
Transcribed Image Text:Use base-ten blocks to illustrate 142 + 5. 142 has flat(s), long(s), and unit(s). Starting with the flats, there are set(s) of 5 flats with remaining. Converting the remaining flats to longs gives a total of long(s), which leads to set(s) of 5 longs with remaining. Converting the remaining longs to units gives a total of unit(s), which leads to set(s) of 5 units with remaining. Therefore, the quotient is with a remainder
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