Use Lagrange multipliers to find the maximum and minimum values off(x, y) = (x + 5)² + (y – 5)?subject to the constraint² + y < 32,if such values exist.If there is no global maximum or global minimum, enter NA in the appropriate answer area.Maximum =Minimum =2 Use Lagrange multipliers to find the maximum and minimum values off(x, y, z) = x² – 8y + 10z?subject to the constraintx² + y? +? = 1,%3Dif such values exist.Enter the exact answers.If there is no global maximum or global minimum, enter NA in the appropriate answer area.Мaximum8Minimum =-8

Given: fx,y=x+52+y-52 & x2+y2≤32 From the Lagrange's multiplier, ∂f∂x=λ ∂g∂x ; ∂f∂y=λ ∂g∂y So,…

Use Lagrange multipliers to find the maximum and minimum values of f(x, y) = (x + 5)² + (y – 5)² subject to the constraint x² + y² < 32, if such values exist. If there is no global maximum or global minimum, enter NA in the appropriate answer area. Maximum = Minimum

Use Lagrange multipliers to find the maximum and minimum values of f(x, y) = (x + 5)² + (y – 5)² subject to the constraint x² + y² < 32, if such values exist. If there is no global maximum or global minimum, enter NA in the appropriate answer area. Maximum = Minimum

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter8: Sequences, Series,and Probability

Section: Chapter Questions

Problem 10CT: Sketch the region corresponding to the system of constraints. Then find the minimum and maximum...

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Q: Constraint:

Question

Use Lagrange multipliers to find the maximum and minimum values of
f(x, y) = (x + 5)² + (y – 5)?
subject to the constraint
² + y < 32,
if such values exist.
If there is no global maximum or global minimum, enter NA in the appropriate answer area.
Maximum =
Minimum =
2

Use Lagrange multipliers to find the maximum and minimum values of
f(x, y, z) = x² – 8y + 10z?
subject to the constraint
x² + y? +? = 1,
%3D
if such values exist.
Enter the exact answers.
If there is no global maximum or global minimum, enter NA in the appropriate answer area.
Мaximum
8
Minimum =
-8

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