Use substitution and partial fractions to find the indefinite integral.√xX 49Step 1Let u =2√x⇒u²dx= x. Differentiate u with respect to x.X u du = dx⇒→ 7Rewrite the integral as follows.212.14 ****dx =X - 494977U/-1(₂₁2uX u2× u) du = /49X +u2298497u98 +98-4) oudu492du ="7u2du2Xu4998+u298- 40 ) du49

The given indefinite integral is The integral formulas are as follows and

Use substitution and partial fractions to find the indefinite integral. 1. Step 1 √x X - 49 dx Let u = √√√x ⇒u² ⇒ 7 Rewrite the integral as follows. 7 |_V= x - √ U² √x dx = X - 49 2 = x. Differentiate u with respect to x. X u du = dx xu) - 49 Xu ../.***. 2 du = - 49 7 98 J(₁) + - 98 +98 49 U du du = 7 49 du X 49 - 98 u 2 98 -49) 00 du

Use substitution and partial fractions to find the indefinite integral. 1. Step 1 √x X - 49 dx Let u = √√√x ⇒u² ⇒ 7 Rewrite the integral as follows. 7 |_V= x - √ U² √x dx = X - 49 2 = x. Differentiate u with respect to x. X u du = dx xu) - 49 Xu ../.***. 2 du = - 49 7 98 J(₁) + - 98 +98 49 U du du = 7 49 du X 49 - 98 u 2 98 -49) 00 du

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter7: Integration

Section7.2: Substitution

Problem 8E: Use substitution to find each indefinite integral. 6x2(2x3+7)32dx

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