Use the Bisection method to approximate the root of the function f(x) = x³ - 7x² + 14x-6, [0,1] and the tolerance error is € = 10-2,
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![Use the Bisection method to approximate the root of the function
f(x) = x³ - 7x² + 14x − 6, [0,1] and the tolerance error is € = 10-².](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2b36003-ef33-455c-bcff-0e6c40acbd92%2F59a3c466-352f-48cd-9f61-e9f166aec81a%2Fky1ml7g_processed.jpeg&w=3840&q=75)
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- Find a root of a equation f(x) = 2x³ - 2x - 5 Using secant bisection method when the initial interval is (a= 1, b= 2) at a required tolerance of f(x)←(-0.003).Approximate the root of the equation f(x) = x^3 - x - 1 using 10 iterations on Bisection Method with range from a = 1 and b = 3.Determine the root of the equation x³ + x² = 1 in the interval [0, 1] by using bisection method.