Use the following information to answer the next question. A monohybrid cross of two pure forms of red flowers and white flowers in Mirabilis jalapa plant with genotypes R1R1 and R2R2 produced all pink flowers. The F2 generation produced a phenotypic and genotypic ratio of 1: 2: 1. Which genetic mechanism can account for these results? O dihybrid cross O incomplete dominance O co-dominance O multiple alleles
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- Using the following information perform following crosses using the forked line and predict all possible phenotypes types of the offspring. List the number and description of the phenotypes of the offspring. 1. aa BB Cc Dd Ee X aa bb Cc Dd EE 2. Ff Rr Gg dd Bb X Ff RR Gg Dd Bb 3. Dd gg JJ bb Hh Ee X DD GG Jj Bb Hh EeAnswer the following with a short solution if needed: a. The gametes of a worm's genotype SsYy should produce what genotypes? b. A genetic cross between two F1-hybrid rose plants having yellow petals will yield what percent green-petal plants in the F2 generation? Yellow petals are dominant to green. c. Brown fur is dominant over light-colored fur. What is the phenotype of the resulting offspring if you cross a heterozygous brown fur and a light-colored fur?Give only typing answer with explanation and conclusion In corn three dominant genes are necessary for aleurone color. The genotype B__D__R is colored. Any homozygous recessive for one gene is colorless. Predict the expected phenotypic ratio COLORED: COLORLESS offspring from the cross of BbDdrr x BbDdRr. The answer is 9:23 Need full explanation
- Consider the following statement: ‘female, w+w flies have red eyes’. In this example: Group of answer choices 1) w+w is the genotype, and red eyes is the phenotype 2) female is the genotype, and red eyes is the phenotype 3) not enough information provided to determine genotype or phenotype 4) red eyes is the genotype, and w+w is the phenotypeEach box represents a potential offspring. Notice that genotypically speaking, they are all the same. Theyare all heterozygous (genotype) which means their phenotype is dark coloration. So, there is 100% chanceof producing a dark eyed, heterozygous offspring. What if that offspring mated with a light eyedindividual? Can you make a Punnett Square for that?Write the Genotypes and Phenotypes of the parents on the left of the square. Complete the square, thenwrite the potential offspring’s genotypes and phenotypes on the right of the square. Parents: Offspring:Genotypes: phenotypes: What are the genotypes of the resulting offspring? What are the phenotypes of the resulting offspring?Use the following information to answer the next four questions. Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Part A: Record the phenotypes and the phenotype ratio in lowest terms. Part B: Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these…
- Use the following information to answer the next four questions. Tomato Plants In tomato plants, round fruit (R) is dominant to oval fruit (r). Pure breeding plants with red and round fruit (FFRR) were crossed to pure breeding plants with yellow and oval fruit (ffrr). The red and round F1 progeny were then testcrossed to plants that were homozygous recessive for both genes (ffrr) with the following results: Phenotypes Number of Offspring Red and round 2 255 Red and oval 290 Yellow and round 310 Yellow and oval 2 145 Part A: Record the phenotypes and the phenotype ratio in lowest terms. Part B: Convert the expected phenotypic ratio from Part A into the expected probability for each of the four phenotypes and record them in the table below. Calculate the probability for each of the four phenotypes observed in the cross from the data presented at the beginning of the question by dividing the number of progeny in each class by the total number of progeny and record these…Answer the following questions. Letter's ONLY 1. A homozygous dominant parent (FF) and a heterozygous parent (Ff) are crossed. What is the genotypic probability of the offspring? * a. 100% Ff b. 50% Ff c. 50% FF and 50% Ff d. 50% Ff and 50% ff e. 50% dominant and 50% recessive f. 100% dominant 2. After performing an experiment on monohybrid cross about the shape of the pea seeds, data were obtained from the result. There are 87 wrinkled pea seeds and 313 round seeds. Of course, round seed is dominant over wrinkled seed. What is the expected value or ratio for the wrinkled seed? * a. 21.75 b. 65.25 c. 100 d. 300 e. 400 f. None of the choicesWhich groups of individuals must show the same phenotype in order to produces a 15:1 phenotypic ratio from a dihybrid cross (CcDd x CcDd) if the trait is affected by duplicate dominant epistasis? Choose the one best (complete) answer. Group of answer choices 1.C_D_, C_dd, and ccD_ 2.C_dd, ccD_, and ccdd 3.C_D_ and ccD_ 4.C_D_ and ccdd 5.C_D_ and C_dd
- in a specific dihybrid cross, the F2 phenotypic ratio is 12:3:1. What is the most likely explanation for this distribution of offspring? And please explain how you got the answer in a small summory for me to understand and learn.Mendelian GeneticsF1 Cross: Yellow, Round x Green, Round GgWw x ggWWCharacter: Pea color & shapeUse Punnett square and fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings. Mendelian GeneticsF1 Cross: Tall, White, Axial x Dwarf, Violet, Terminal DdwwAA x ddWWaaCharacter: Stem height, Flower color & positionUse fork-line method to check the F2.Show and interpret all the possible genotypes and phenotypes of the offsprings. I. For A and B,1. Identify the type of inheritance. Justify your answer.2. Decode the genotypes of the individuals in the pedigree. (Use letter A for representation of alleles.)3. List down all affected individuals.B.A.What is the correct table in these two given? 1. Take two coins and assume that heads represent the dominantallele (A) and tails represents the recessive allele (a). The genotype for each coin isheterozygous (Aa).2. Assume that each coin represents one parent. When a single coin is flipped, one gameteis formed (through the process of meiosis). If the flipped coin is on heads, then thegamete has the dominant allele (A). When both coins are flipped simultaneously, therewill be two possible gametes that can combine through fertilization to form a zygote. Eachtime you flip both coins, you will record the “genotype” of the offspring.3. Flip the coins 100 times and record your results in the chart below