Use the formula below to find the instantaneous rate of change of the function at the given x-value. f(x) = 3x2 + x - 5 at x = 5 Average and Instantaneous Rate of Change The average rate of change of a function f between x and x + h is F(x + h) – F(x). (Difference quotient gives the average rate of change.) h The instantaneous rate of change of a function fat the number x is f(x + h) – fx) lim (Taking the limit makes it instantaneous.) h

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Chapter6: Exponential And Logarithmic Functions
Section6.8: Fitting Exponential Models To Data
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Use the formula below to find the instantaneous rate of change of the function at the given x-value.
f(x) = 3x2 + x − 5   at   x = 5
  • Average and Instantaneous Rate of Change▲
    The average rate of change of a function f between x and 
    x + h
     is
    f(x + h) − f(x)
    h
    .
     (Difference quotient gives the average rate of change.)
    The instantaneous rate of change of a function f at the number x is
    lim h→0 
    f(x + h) − f(x)
    h
     (Taking the limit makes it instantaneous.)
Use the formula below to find the instantaneous rate of change of the function at the given x-value.
F(x) = 3x2 + x - 5 at x = 5
Average and Instantaneous Rate of Change
The average rate of change of a function f between x and x + h is
f(x + h) – F(x). (Difference quotient gives the average rate of change.)
The instantaneous rate of change of a function fat the number x is
f(x + h) – f(x)
lim
(Taking the limit makes it instantaneous.)
h-0
Transcribed Image Text:Use the formula below to find the instantaneous rate of change of the function at the given x-value. F(x) = 3x2 + x - 5 at x = 5 Average and Instantaneous Rate of Change The average rate of change of a function f between x and x + h is f(x + h) – F(x). (Difference quotient gives the average rate of change.) The instantaneous rate of change of a function fat the number x is f(x + h) – f(x) lim (Taking the limit makes it instantaneous.) h-0
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