# Use the graph below to determine the equation of the circle in (a) center-radiusa. Type the equation in center-radius formform and (b) general form(Simplify your answer.)10-5.7(-8,4) 24)1010

Question
25 views help_outlineImage TranscriptioncloseUse the graph below to determine the equation of the circle in (a) center-radiusa. Type the equation in center-radius form form and (b) general form (Simplify your answer.) 10 -5.7 (-8,4) 24) 10 10 fullscreen
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Step 1

Formula used:

Equation of circle whose centre (h, k) and radius r is

(x - h)2 + (y - k)2 = r2

Step 2

According to the given graph the centre is the mid point of (-8, 4) and (-2, 4) is

(h, k) = [(-8-2)/2, (4+4)/2]

(h, k) = (-5, 4)

And diameter is distance between ((-8, 4) and (2, 4) is

Step 3

a) So equation of circle whose centre is (-5 , 4) and radius 3 ...

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