Use the graph to determine the limit. (If an answer does not exist, enter DNE.) (a) lim f(x) = x→ct (b) lim f(x) = х-с (c) lim f(x) = X-C Yes No -B Need Help? C = -2 Is the function continuous at x = -2? -2 (-2,-3) Read It 1 y 2 -21 -4 X
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- given y= f(x)= 2^2-9x+20/x-4 Why is it not possible to apply the quotient limit theroem to find the limit of this function as x approaches 4?Calculate the limit algebraically. (If an answer does not exist, enter DNE.) lim h→0 8h2 + h 3h2 + 3h - ________________ If the limit does not exist, say why. (If the limit does exist, so state.) -The limit does not exist because one side diverges to ∞ and the other side diverges to −∞. -The limit does not exist because only one of the left or right limits exists as a finite value. -The limit does not exist because the left and right limits exist but are not the same finite value. -The limit does not exist because it diverges to ∞ or −∞. -The limit does exist and is a finite number.In the exercise below, the initial substitution of x=a yields the form 0/0. Look for ways to simplify the function algebraically, or use a table and/or graph to determine the limit. When necessary, state that the limit does not exist.
- Use the graph to determine the limit. (If an answer does not exist, enter DNE.) lim x→c+ f(x) =Use the graph to find the limit L (if it exists). If the limit does not exist, explain why. (If an answer does not exist, enter DNE.) g(x) = −2x x − 2 (a) lim x→2 g(x) L = The limit does not exist at x = 2 because the function does not approach f(2) as x approaches 2.The limit does not exist at x = 2 because the function is not continuous at any x value. The limit does not exist at x = 2 because f(2) ≠ 2.The limit does not exist at x = 2 because the function increases and decreases without bound as x approaches 2.The limit exists at x = 2. (b) lim x→0 g(x) L = The limit does not exist at x = 0 because the function does not approach f(0) as x approaches 0.The limit does not exist at x = 0 because the function is not continuous at any x value. The limit does not exist at x = 0 because f(0) ≠ 0.The limit does not exist at x = 0 because the function increases and decreases without bound as x approaches 0.The limit exists at x = 0.