Use the graph y=g (x) to graph the given function. 12 9. 3. 12 9 -6 -3 376 12 -3. y g (x) -6 -12- y= 5g (x) 337y 30 18 15 12 -12 -3 -3 12 -6- -12 -15 -18 -21 -24 -27 30 -33
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Q: 1.3 Calculate the domain end range of the following graph function: 10 D:[-10, co0), R:(-0, 00) D:…
A: Since you have posted multiple questions i can do first question as per our company guidelines…
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Q: Which of the following represent the graph? 4 21 1- 9. 4 3 1 2. 4 5. 6 7. -1 -2 1 O f (x) – 2 (x+3)…
A: To find : Which of the following that represent the given graph.
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A: A graph
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A: NOTE: Refresh your page if you can't see any equations. . the given graph is
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A: Explanation of the answer is as follows
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Q: Which of the following describes the graph of h(x) = −3(x − 1)²(x + 1)²(x + 2)? O-12 O -10 -0 -4 -12…
A: see below the answer and explanation
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A: find the intercepts
Q: 5 The graph below is g(x) 0/1 6. 4 -2 O2 4 6 10 12 -2 4 What is x if g(x) = -2? 8. 2.
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A: Graphical transformation
Q: 5. Given that f(x)= |x|, h(x)=-x, g(x)=(x-2)²-3 . (a) Graph f(x),h(x) and g(x). (b) Using the…
A: f(x)=x, h(x)=-x, g(x)=(x-2)2-3
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Q: (a) If f(x) = x4 + 3x, find f'(x). f'(x) =| (b) Check to see that your answer to part (a) is…
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Q: 9. Below is the graph of (x). For what values of x is fx) concave down? 2/4 -3 -2 с. х>1 d. x 1 a.…
A: Since you have asked multiple question, we will solve the first question for you. If youwant any…
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A: We used graphing tool for plotting the graph. GeoGebra is used to plot the given graph.
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A: The domain of a function is the set of all possible inputs for the function.
Q: 3 Graph the function y =x-3. 10 8. 4. -2 -6 -8 -10 -10 4 -2 2 4 6 8 10 ? y = -x-3 4
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Q: 9. Graph the piecewise function: 2 xS-1 h(x) = { x' -1<x< /2 %3D 43
A: We have to graph the function.
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Q: 3. Given the graph of f(x), sketch the graph of y = S(x)* a) b) 2- -8-7 -6-5-43-2-1 123 5678 -2 -4…
A: (a) Here is the given graph, It is the graph of a quadratic function,
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Q: 2) The graph of the function +1, if 0 <r<5 f(x) = 3V5VT 51 if 5 <r< 10 is given in the figure below.
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- (a) To obtain the graph of g(x)=2x1 , we start with the graph of f(x)=2x and shift it _____________ (upward/ downward) 1 unit. (b) To obtain the graph of h(x)=2x1 , we start with the graph of f(x)=2xand shift it to the (left/right) 1unit.In this problem you are asked to find a function that models in real life situation and then use the model to answer questions about the guidelines on page 273 to help you. Minimizing Time A man stands at a point A on the bank of a straight river, 2 mi wide. To reach point B, 7 mi downstream on the opposite bank, he first rows his boat to point Pon the opposite bank and then walks the remaining distances x to B, as shown in the figure. He can row at a speed or 2 mi/h and walk as a speed of mi/h (a) Find a function that models the time needed for the trip. (b) Where should he land so that he reaches B as soon as possible?(a) Suppose we shift the graph of f vertically downwards by h units such that the maximum turning points (vertices) of the resulting graph lie one unit below the x-axis. What is the value of h? (b) Suppose we shift the graph of g vertically upwards by l units such that the part of the graph of g that lies below the x-axis results in touching the x-axis. What is the value of l?
- 1) How is the graph of the entire function different from the graph for the real-life situation? 2) Determine increasing interval(s) of the function if it exists. 3) Determine decreasing interval(s) of the function if it exists. 4) As n becomes very large, what happens to C?The graph of a function f is given. The x y-coordinate plane is given. A curve with 2 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the x-axis at x = −1, and ends at the open point (0, −1). The second part is linear, begins at the closed point (0, 2), goes down and right, crosses the x-axis at x = 2, and exits the window in the fourth quadrant. Determine whether f is continuous on its domain. continuous not continuous If it is not continuous on its domain, say why. lim x→0 f(x) ≠ f(0) lim x→0+ f(x) ≠ lim x→0− f(x), so lim x→0 f(x) does not exist. The graph has discontinuities at the end points. The graph is continuous on its domain.Let C(x) denote the total cost of manufacturing x units of some product. Then C(x) is an increasing function for all x. For small values of x, the rate of increase of C(x) decreases (because of the savings that are possible with “mass production”). Eventually, however, for large values of x, the cost C(x) increases at an increasing rate. (This happens when production facilities are strained and become less efficient.) Sketch a graph that could represent C(x).
- The graph of a function f is given. The x y-coordinate plane is given. A curve with 3 parts is graphed. The first part is linear, enters the window in the second quadrant, goes down and right, crosses the x-axis at approximately x = −0.33, crosses the y-axis at y = −0.25, and ends at the open point (1, −1). The second part is the point (1, 1). The third part is linear, begins at the open point (1, −1), goes up and right, crosses the x-axis at x = 2, and exits the window in the first quadrant. Determine whether f is continuous on its domain. continuous not continuous If it is not continuous on its domain, say why. lim x→1+ f(x) ≠ lim x→1− f(x), so lim x→1 f(x) does not exist. The function is not defined at x = 1. The graph is continuous on its domain. lim x→1 f(x) = −1 ≠ f(1)1)Find the value of c so that the domain of f(x) = √c-x^2! will be [-5,5]. 2)Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. The graph of a function cannot have symmetry with respect to the x-axis.1. The graph of a function y=f(x) always crosses the y-axis. True or False2. Every graph represents a function.A. the statement is true because every graph associates a unique x-value for each y-valueB. the statement is true because every graph associates a unique y-value for each x-valueC. the statement is false because a graph that crosses the x-axis two times does not represent a functionD. the statement is false because a graph that crosses the y-axis two times does not represent a functionI need those answers solution
- Functions of the form f(x) = 5 · bkx for k = ±1 will be examined to study the effect of the parameter b on the graph. (a) Graph the function f(x) =5 · 2x. Use the graph to determine the y-values at x-values of −2, −1, 0, 1, and 2. For every increase of 1 in the x-value, the y-value can be found from the previous y-value by ---Select--- the addition of a constant multiplication by a constant . The constant is equal to . (b) Graph the function f(x) = 5 · 0.5x. Use the graph to determine the y-values at x-values of −2, −1, 0, 1, and 2. For every increase of 1 in the x-value, the y-value can be found from the previous y-value by ---Select--- the addition of a constant multiplication by a constant . The constant is equal to . (c) Graph the function f(x) = 5 · 2−x. Use the graph to determine the y-values at x-values of −2, −1, 0, 1, and 2. For every increase of 1 in the x-value, the y-value can be found from the previous y-value by ---Select--- the addition of a…the point (3,20) on graph y=f(x)Does the values of y have to be the same in axis of symmetry and vertex in functions when they are positive and negative. So like, for instance, if x = -1, that results in y = 2; so if x will equal 1, will y equal 2 as well? For e.x. - Graph the function y= -4x^2+4x+8. Find the vertex and the axis of symmetery.