P. 29 Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval.x4 + x - 6 = 0, (1, 2)f(x) = x4 + x – 6 is--Select-- on the closed interval [1, 2], f(1) =and f(2) =Since -4 < ? - < 12, there is a number c in (1, 2) such that f(c) = ?v by theIntermediate Value Theorem. Thus, there is a --Select---of the equation x4 + x – 6 = 0 in the interval (1, 2).

f(x) = x4 + x - 6 ƒ is continuous over the closed interval [a, b] if and only if it's continuous on…

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x4 + x - 6 = 0, (1,2) f(x) = x + x - 6 is --Select- v on the closed interval [1, 2], f(1) = Intermediate Value Theorem. Thus, there is a --Select-- v of the equation x + x Since -4 < ? v < 12, there is a number c in (1, 2) such that f(c) = ? v by the and f(2) = 6 = 0 in the interval (1, 2).

Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x4 + x - 6 = 0, (1,2) f(x) = x + x - 6 is --Select- v on the closed interval [1, 2], f(1) = Intermediate Value Theorem. Thus, there is a --Select-- v of the equation x + x Since -4 < ? v < 12, there is a number c in (1, 2) such that f(c) = ? v by the and f(2) = 6 = 0 in the interval (1, 2).

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter4: Polynomial And Rational Functions

Section4.5: Rational Functions

Problem 51E

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