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Use the linear approximation to estimate Af = f(3.2) – f(3) for f(x) = 13 1+x? (Use decimal notation. Give your answer to three decimal places.) Af = Estimate the actual change. (Use decimal notation. Give your answer to six decimal places.) Af = Compute the error and the percentage error in the linear approximation. (Use decimal notation. Give your answer to six decimal places.)

Use the linear approximation to estimate Af = f(3.2) – f(3) for f(x) = 13 1+x? (Use decimal notation. Give your answer to three decimal places.) Af = Estimate the actual change. (Use decimal notation. Give your answer to six decimal places.) Af = Compute the error and the percentage error in the linear approximation. (Use decimal notation. Give your answer to six decimal places.)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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Use the linear approximation to estimate Af = f(3.2) – f(3) for f(x) = . (Use decimal notation. Give your answer to three decimal places.) Af a Estimate the actual change. (Use decimal notation. Give your answer to six decimal places.) Af = Compute the error and the percentage error in the linear approximation. (Use decimal notation. Give your answer to six decimal places.) The error in the Linear Approximation is Question Source: Rogawski 4e Calculus Early Transcendentals | Publisher: W.H. Freeman
Transcribed Image Text:Use the linear approximation to estimate Af = f(3.2) – f(3) for f(x) = . (Use decimal notation. Give your answer to three decimal places.) Af a Estimate the actual change. (Use decimal notation. Give your answer to six decimal places.) Af = Compute the error and the percentage error in the linear approximation. (Use decimal notation. Give your answer to six decimal places.) The error in the Linear Approximation is Question Source: Rogawski 4e Calculus Early Transcendentals | Publisher: W.H. Freeman
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f\left(x\right)=\frac{13}{1+x^2}

take x=3

f\left(3\right)=\frac{13}{1+3^2}

f\left(3\right)=\frac{13}{1+9}

f\left(3\right)=\frac{13}{10}

f\left(3\right)=1.3

the point on the curve is 

(x_1,y_1)=(3,1.3)

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