Use the Squeeze Theorem to show that lim (x² cos 21xx) = 0. Illustrate by graphing the functions f(x) = -x², g(x) = x² cos 21xx, and h(x) = x² on the same screen. Let f(x) = -x2, g(x) = x² cos 21xx, and h(x) = x². Then ? v < cos 21xx < ? ♥ lim f(x) = lim h(x) = vs x² cos 21xx s? Since by the Squeeze Theorem we have lim g(x) =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 14T
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Use the Squeeze Theorem to show that
lim (x2 cos 21TX) = 0. Illustrate by graphing the functions f(x) = -x², g(x) = x² cos 21Tx, and h(x) = x² on the
X → 0
same screen.
Let f(x) = -x², g(x) = x² cos 21ax, and h(x) = x². Then ? v < cos 2lxx <?
lim f(x) =
v < x cos 21xx <?
Since
lim h(x)
by the Squeeze Theorem we have lim g(x)
Transcribed Image Text:Use the Squeeze Theorem to show that lim (x2 cos 21TX) = 0. Illustrate by graphing the functions f(x) = -x², g(x) = x² cos 21Tx, and h(x) = x² on the X → 0 same screen. Let f(x) = -x², g(x) = x² cos 21ax, and h(x) = x². Then ? v < cos 2lxx <? lim f(x) = v < x cos 21xx <? Since lim h(x) by the Squeeze Theorem we have lim g(x)
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