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Use the worked example above to help you solve this problem. A proton is released from rest at x= -2.00 cm in a constant electric field with magnitude 1.50 x 10 N/C pointing in the positive x-direction. (a) Assuming an initial speed of zero, find the speed of a proton at x= 0.0600 m with a potential energy of-1.92 x 1017 1. (Assume the potential energy at the point of release is zero.) m/s (b) An electron is now fired in the same direction from the same position. Find the initial speed of the electron (at x = -2.00 cm) given that its speed has fallen by half when it reaches X = 0.190 m, a change in potential energy of 5.05 x 1017 J. m/s

Use the worked example above to help you solve this problem. A proton is released from rest at x= -2.00 cm in a constant electric field with magnitude 1.50 x 10 N/C pointing in the positive x-direction. (a) Assuming an initial speed of zero, find the speed of a proton at x= 0.0600 m with a potential energy of-1.92 x 1017 1. (Assume the potential energy at the point of release is zero.) m/s (b) An electron is now fired in the same direction from the same position. Find the initial speed of the electron (at x = -2.00 cm) given that its speed has fallen by half when it reaches X = 0.190 m, a change in potential energy of 5.05 x 1017 J. m/s

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...... PRACTICE IT Use the worked example above to help you solve this problem. A proton is released from rest at x = -2.00 cm in a constant electric field with magnitude 1.50 x 10 N/C pointing in the positive x-direction. (a) Assuming an initial speed of zero, find the speed of a proton at x = 0.0600 m with a potential energy of -1.92 x 1017 ). (Assume the potential energy at the point of release is zero.) m/s (b) An electron is now fired in the same direction from the same position. Find the initial speed of the electron (at x = -2.00 cm) given that its speed has fallen by half when it reaches x = 0.190 m, a change in potential energy of 5.05 x 1017 J. m/s EXERCISE HINTS: GETTING STARTED I I'M STUCKI The electron in part (b) travels from x - 0.190 m (where it has half the initial speed you previously calculated) to x = -0.140 m within the constant electric field. If there's a change in electric potential energy of -7.93 x 1017) as it goes from x = 0.190 m to x= -0.140 m, find the electron's speed at x- -0.140 m. (Note: Use the values from the Practice It section. Account for the fact that the electron may turn around during its travel.) V m/s
Transcribed Image Text:...... PRACTICE IT Use the worked example above to help you solve this problem. A proton is released from rest at x = -2.00 cm in a constant electric field with magnitude 1.50 x 10 N/C pointing in the positive x-direction. (a) Assuming an initial speed of zero, find the speed of a proton at x = 0.0600 m with a potential energy of -1.92 x 1017 ). (Assume the potential energy at the point of release is zero.) m/s (b) An electron is now fired in the same direction from the same position. Find the initial speed of the electron (at x = -2.00 cm) given that its speed has fallen by half when it reaches x = 0.190 m, a change in potential energy of 5.05 x 1017 J. m/s EXERCISE HINTS: GETTING STARTED I I'M STUCKI The electron in part (b) travels from x - 0.190 m (where it has half the initial speed you previously calculated) to x = -0.140 m within the constant electric field. If there's a change in electric potential energy of -7.93 x 1017) as it goes from x = 0.190 m to x= -0.140 m, find the electron's speed at x- -0.140 m. (Note: Use the values from the Practice It section. Account for the fact that the electron may turn around during its travel.) V m/s
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