USE this part to write SQL statements Branch(branch_id:integer, branch_name:varchar(50), branch_location:varchar(40), money_on_hand:numeric(15,2) create table Branch (branch_id integer, branch_name varchar(50), branch_location varchar(40), money_on_hand numeric(15,2), primary key (branch_id)); Loan(loan_number:integer, branch_id:integer, amount:numeric(8,2)) foreign key branch_id references Branch(branch_id) create table Loan (loan_number integer, branch_id integer, amount numeric(8,2), primary key (loan_number), foreign key (branch_id) references Branch (branch_id)); Customer(customer_id:integer, customer_last_name:varchar(35),customer_first_name:varchar(25), customer_street:varchar(30), customer_zip:integer) create table Customer (customer_id integer, customer_last_name varchar(35), customer_first_name varchar(25), customer_street varchar(30), customer_zip integer, primary key (customer_id)); Borrower(customer_id:integer, loan_number:integer) foreign key (customer_id) references Customer(customer_id) foreign key (loan_number) references Loan(loan_number) create table Borrower (customer_id integer, loan_number integer, primary key (customer_id, loan_number), foreign key (customer_id) references Customer (customer_id), foreign key (loan_number) references Loan (loan_number)); Depositor(customer_id:integer, account_number:integer) foreign key (customer_id) references Customer(customer_id) foreign key (account_number) references Account(account_number) Note: as the Account table is a referenced table, you have to create that table first. create table Depositor (customer_id integer, account_number integer, primary key (customer_id, account_number), foreign key (customer_id) references Customer (customer_id), foreign key (account_number) references Account (account_number)); Account(account_number:integer, branch_id:integer, balance:numeric(8,2)) foreign key branch_id references Branch(branch_id) create table Account (account_number integer, branch_id integer, balance numeric(8,2), primary key (account_number), foreign key (branch_id) references Branch (branch_id)); Write SQL statements to answer the following questions using Assignment 3’s schema (tables from part 1). You can add more data to the tables if you want, just follow the PK and FK rules. Accounts are not Loans and Loans are not Accounts. 1- Find how many branches have loans between $4,100.00 and $7,000.00. HINT: Do not manually count the rows, have the DBMS engine do the work. 2- For each branch, find the Min and Max loan amounts. Your output should include Branch Id, min loan amount and max loan amount for that Branch. 3- Find how many accounts there are for each customer. The output should include customer id and number of accounts for that customer. 4- Find the average account balance for each Branch. The output should be a list of Branch Id and for each Branch Id, the average account balance in that Branch. 5- Find Customer ID, Customer name and Customer City for all accounts, sorted by Customer City, then Customer Last name. 6- Find Customer ID, Customer name and the number of loans for each Customer. 7- Find Loan number and Customer Id of the loan with the lowest amount. 8- Create a view called Gary_Branch_V that contains Branch Id, Branch name, and number of loans for each Branch that is in the city of Gary. 9- For each Customer in Hopkins, find the balance in their account(s). 10- Find how many different accounts each customer has at each Branch. The output should be a list of Customer ID and for each Customer ID, the number of accounts for this customer by Branch ID. 11- Find the branch with the highest or largest Average loan amount. List the Branch ID, Branch Name, and the Highest Average loan amount.
USE this part to write SQL statements
- Branch(branch_id:integer, branch_name:varchar(50), branch_location:varchar(40), money_on_hand:numeric(15,2)
create table Branch
(branch_id integer,
branch_name varchar(50),
branch_location varchar(40),
money_on_hand numeric(15,2),
primary key (branch_id));
- Loan(loan_number:integer, branch_id:integer, amount:numeric(8,2))
foreign key branch_id references Branch(branch_id)
create table Loan
(loan_number integer,
branch_id integer,
amount numeric(8,2),
primary key (loan_number),
foreign key (branch_id) references Branch (branch_id));
- Customer(customer_id:integer, customer_last_name:varchar(35),customer_first_name:varchar(25), customer_street:varchar(30), customer_zip:integer)
create table Customer
(customer_id integer,
customer_last_name varchar(35),
customer_first_name varchar(25),
customer_street varchar(30),
customer_zip integer,
primary key (customer_id));
- Borrower(customer_id:integer, loan_number:integer)
foreign key (customer_id) references Customer(customer_id)
foreign key (loan_number) references Loan(loan_number)
create table Borrower
(customer_id integer,
loan_number integer,
primary key (customer_id, loan_number),
foreign key (customer_id) references Customer (customer_id),
foreign key (loan_number) references Loan (loan_number));
- Depositor(customer_id:integer, account_number:integer)
foreign key (customer_id) references Customer(customer_id)
foreign key (account_number) references Account(account_number)
Note: as the Account table is a referenced table, you have to create that table first.
create table Depositor
(customer_id integer,
account_number integer,
primary key (customer_id, account_number),
foreign key (customer_id) references Customer (customer_id),
foreign key (account_number) references Account (account_number));
- Account(account_number:integer, branch_id:integer, balance:numeric(8,2))
foreign key branch_id references Branch(branch_id)
create table Account
(account_number integer,
branch_id integer,
balance numeric(8,2),
primary key (account_number),
foreign key (branch_id) references Branch (branch_id));
Write SQL statements to answer the following questions using Assignment 3’s schema (tables from part 1). You can add more data to the tables if you want, just follow the PK and FK rules. Accounts are not Loans and Loans are not Accounts.
1- Find how many branches have loans between $4,100.00 and $7,000.00. HINT: Do not manually count the rows, have the DBMS engine do the work.
2- For each branch, find the Min and Max loan amounts. Your output should include Branch Id, min loan amount and max loan amount for that Branch.
3- Find how many accounts there are for each customer. The output should include customer id and number of accounts for that customer.
4- Find the average account balance for each Branch. The output should be a list of Branch Id and for each Branch Id, the average account balance in that Branch.
5- Find Customer ID, Customer name and Customer City for all accounts, sorted by Customer City, then Customer Last name.
6- Find Customer ID, Customer name and the number of loans for each Customer.
7- Find Loan number and Customer Id of the loan with the lowest amount.
8- Create a view called Gary_Branch_V that contains Branch Id, Branch name, and number of loans for each Branch that is in the city of Gary.
9- For each Customer in Hopkins, find the balance in their account(s).
10- Find how many different accounts each customer has at each Branch. The output should be a list of Customer ID and for each Customer ID, the number of accounts for this customer by Branch ID.
11- Find the branch with the highest or largest Average loan amount. List the Branch ID, Branch Name, and the Highest Average loan amount.
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