use trig substitution to find integral of 1/[3t^2(6-t^2)^(1/2). that is numerator is 1 denominator is 3 t-squared times the square root of 6-t-squared. I tried letting t=square root of six times cosx. I worked it to the point where I have 1 over 18 times square root 6 times cos^2(x) sin(x). then i brought those to numerator in the form of sec^2(x)csc(x) with 1 over 18 square root 6 going outside of the integral. If I did this correct up to this point, how can I solve if it is in terms of sec and csc? Thanks!

use trig substitution to find integral of 1/[3t^2(6-t^2)^(1/2). that is numerator is 1 denominator is 3 t-squared times the square root of 6-t-squared. I tried letting t=square root of six times cosx. I worked it to the point where I have 1 over 18 times square root 6 times cos^2(x) sin(x). then i brought those to numerator in the form of sec^2(x)csc(x) with 1 over 18 square root 6 going outside of the integral. If I did this correct up to this point, how can I solve if it is in terms of sec and csc? Thanks!

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter2: Graphical And Tabular Analysis

Section2.1: Tables And Trends

Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...

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