Use variation of parameters to find a general solution to the differential equation given that the functions y₁ and y₂ are linearly independent solutions to the corresponding homogeneous equation for t> 0. ty" +(3t-1)y'-3y=9t²e-3t. Y₁ =3t-1, Y₂ = e-3t -31. A general solution is y(t) = c₁ (3t-1)+c₂e²³ -31

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