Using C Language, what is the output of this code?
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Using C Language, what is the output of this code?
#include<stdio.h>
#include<conio.h>
#define r 3
#define c 4
int z[r][c] = {1,2,3,4,5,6,7,8,9,10,11,12};
main()
{
int a, b, c = 999;
clrscr();
for(a=0;a<r;++a)
for(b=0;b<c;++b
if(z[a][b]<c)
c=z[a][b];
printf(“%d”,c);
getch();
return 1;
)
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- 1.Put the code into a complete C program int i = 0; void func(char *str1, char *str2) { char *ptr = malloc(sizeof(int)); char buf[1024]; int j; static int y; } 2. Compile the program using gcc in Linux. 3. Use gdb to debug and print the addresses of variables in the code. 4. Draw the stack frame of func() and point out the addresses of related variables.Consider the following C++ code: static long z = 5 ; int d = 10 ; int *ptr1 = new int[2] ; void myfun ( int param1 ){ static int x = 100 ; float y = 50; int *ptr2 = new int ; // . . .; delete ptr2 ; delete ptr1 ; } void fun2() { static int num =5; int var = 10; } Identify the storage bindings types, storage locations and lifetime of each variable. Select one for storage binding types: static, stack dynamic, explicit heap dynamic, implicit dynamic Select one for storage locations: static segment, stack, heap. Select one for lifetimes: Entire program, Execution of funct1, From Line ... to Line ...Question:- 1 Recreate the following C program in x86-64 and aarch64 assembly manually: #include <stdio.h> typedef struct _v2d {long x;long y;} v2d_t; static long dot(v2d_t a, v2d_t b){return a.x * b.x + a.y * b.y;} static long dot_ptr(v2d_t *a, v2d_t *b){return a->x * b->x + a->y * b->y;} int main(void){v2d_t a, b; scanf("%ld %ld %ld %ld", &a.x, &a.y, &b.x, &b.y); long res1 = dot(a, b);printf("%ld\n", res1); long res2 = dot_ptr(&a, &b);printf("%ld\n", res2); return 0;}
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