Using Kepler's laws of planetary motion, we can derive the following expression for a circular orbit: where T2 = 4π²a³ .3 fl Torbital period a= orbital radius in km = distance from the center of the earth to the orbit = Kepler's constant = 3.986004418 x 105 km³/s² The earth rotates once per sidereal day of 23 h 56 min 4.09 s (a) Determine the orbital radius of a GEO satellite (b) Assuming an earth radius of 6 370 km what is the orbit height h (1)

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A: Answer= 8/9. The answer provided below has been developed in a clear step by step manner.

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